SQL Server發送狀態到電子郵件

Question

嘿大家都希望一切都好。我需要你的專業知識。

我有一個HTML的形式和它裏面我有一個下拉選項中選擇一個狀態

<select name="State"> 
    <option value="0" selected="selected">Select a State</option> 
    <option value="AL">Alabama</option> 
    <option value="AK">Alaska</option> 
    <option value="AZ">Arizona</option> 
    <option value="AR">Arkansas</option> 
     etc..... 
</select> 

任何時間客戶選擇AA狀態，並提交它去我的SQL Server數據庫和表格獲取與他們在html表單中選擇的狀態相關的IP地址。

+-----------+-------+---------------+ 
| stateip_id| state | user_ip  | 
+-----------+-------+---------------+ 
|  1 | AL | 67.100.244.74 | 
|  2 | AK | 68.20.131.135 | 
|  3 | AZ | 64.134.225.33 | 
+-----------+-------+---------------+ 

因此，舉例來說，可以說，他們選擇阿拉巴馬（AL），當他們提交表單我想要的代碼連接到PHP文件，然後顯示相關的狀態的IP地址，在此情況下（ AL）。我對這個感謝這個論壇的一些PHP代碼和其他

<?php 
// visit http://php.net/pdo for more details 
// start error handling 

try 
{ 
$Server = "00.00.000.000,0000"; 
$User = "username"; 
$Pass = "password"; 
$DB = "dbname"; 

//connection to the database 
$dbhandle = mssql_connect($Server, $User, $Pass) 
    or die("Couldn't connect to SQL Server on $Server"); 

//select a database to work with 
$selected = mssql_select_db($DB, $dbhandle) 
    or die("Couldn't open database $DB"); 

$state = $_POST['State']; 

$query = "SELECT TOP 1 user_ip 
       FROM state_ip 
       WHERE state='$state' 
       ORDER BY newid()"; 

//execute the SQL query and return records 
$result = mssql_query($query); 

$numRows = mssql_num_rows($result); 
echo "<h1>" . $numRows . " Row" . ($numRows == 1 ? "" : "s") . " Returned </h1>"; 

//display the results 
while($row = mssql_fetch_array($result)); 

} 
catch (Exception $e) 
{ 
    echo "sorry, there was an error."; 
    mail("email@gmail.com", "database error", $e->getMessage(), "From: email@gmail.com"); 
} 

if(isset($_POST['email'])) { 

    // EDIT THE 2 LINES BELOW AS REQUIRED 
    $email_to = "email@gmail.com"; 
    $email_subject = "This is a test"; 


    function died($error) { 
     // your error code can go here 
     echo "We are very sorry, but there were error(s) found with the form you submitted. "; 
     echo "These errors appear below.<br /><br />"; 
     echo $error."<br /><br />"; 
     echo "Please go back and fix these errors.<br /><br />"; 
     die(); 
    } 

    // validation expected data exists 
    if(!isset($_POST['first_name']) || 
     !isset($_POST['last_name']) || 
     !isset($_POST['email']) || 
     !isset($_POST['what']) || 
     !isset($_POST['State']) || 
     !isset($_POST['comments'])) { 
     died('We are sorry, but there appears to be a problem with the form you submitted.');  
    } 

    $what = $_POST['what']; // required 
    $first_name = $_POST['first_name']; // required 
    $last_name = $_POST['last_name']; // required 
    $email_from = $_POST['email']; // required 
    $state = $_POST['State']; // not required 
    $comments = $_POST['comments']; // required 

    $error_message = ""; 
    $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/'; 
    if(!preg_match($email_exp,$email_from)) { 
    $error_message .= 'The Email Address you entered does not appear to be valid.<br />'; 
    } 
    $string_exp = "/^[A-Za-z .'-]+$/"; 
    if(!preg_match($string_exp,$first_name)) { 
    $error_message .= 'The First Name you entered does not appear to be valid.<br />'; 
    } 
    if(!preg_match($string_exp,$last_name)) { 
    $error_message .= 'The Last Name you entered does not appear to be valid.<br />'; 
    } 
    if(strlen($comments) < 2) { 
    $error_message .= 'The Comments you entered do not appear to be valid.<br />'; 
    } 
    if(strlen($error_message) > 0) { 
    died($error_message); 
    } 
    $email_message = "Form details below.\n\n"; 

    function clean_string($string) { 
     $bad = array("content-type","bcc:","to:","cc:","href"); 
     return str_replace($bad,"",$string); 
    } 

    $email_message .= "First Name: ".clean_string($first_name)."\n"; 
    $email_message .= "Last Name: ".clean_string($last_name)."\n"; 
    $email_message .= "What: ".clean_string($what)."\n"; 
    $email_message .= "Email: ".clean_string($email_from)."\n"; 
    $email_message .= "State: ".clean_string($state)."\n"; 
    $email_message .= "Comments: ".clean_string($comments)."\n"; 
// create email headers 
$headers = 'From: '.$email_from."\r\n". 
'Reply-To: '.$email_from."\r\n" . 
'X-Mailer: PHP/' . phpversion(); 
if (!mail($email_to, $email_subject, $email_message, $headers)) 
{ 
    echo "failed to send message"; 
} 

?> 


<!-- include your own success html here --> 

Thank you for contacting us. We will be in touch with you very soon. 

<?php 
} 
?> 

這上面的代碼的偉大工程，我收集了隨機狀態並與形式的信息的其餘部分發送到我的郵箱。我遇到的問題是，在發送給我的郵件中，例如發送給我「AL或AZ或CA等」。它不會向我發送IP地址。我認爲它與這行代碼有關

$email_message .= "State: ".clean_string($state)."\n"; 

主要是$ state部分。我希望它選擇user_ip部分，但不知道如何去做。我曾經試過，但它不工作

$email_message .= "State: ".clean_string('user_ip')."\n"; 

這是怎麼顯示在一封電子郵件中

First Name: afdf 
Last Name: sfgsdf 
What: hellow 
Email: sd@fd.com 
State: AL 
Comments: ali alabama2 

我想這是這個

First Name: afdf 
Last Name: sfgsdf 
What: hellow 
Email: sd@fd.com 
State: 123.456.1.21 
Comments: ali alabama2 

Answer 1

它做什麼你」已經將它編碼爲：

$email_message .= "State: ".clean_string($state)."\n"; 

你填充變量$ result這裏的IP地址：

$query = "SELECT TOP 1 user_ip 
       FROM state_ip 
       WHERE state='$state' 
       ORDER BY newid()"; 

//execute the SQL query and return records 
$result = mssql_query($query); 

所以，你真的需要$結果，而不是$狀態：

$email_message .= "State: ".clean_string($result)."\n";