發送電子郵件

Question

這裏MimeText用於當UTF-8編碼的問題是我的代碼，發送電子郵件的一部分：

servidor = smtplib.SMTP() 
servidor.connect(HOST, PORT) 
servidor.login(user, usenha) 
assunto = str(self.lineEdit.text()) 
para = str(globe_email)    
texto = self.textEdit.toPlainText() 
textos = str(texto) 
corpo = MIMEText(textos.encode('utf-8'), _charset='utf-8') 
corpo['From'] = user 
corpo['To'] = para 
corpo['Subject'] = assunto 
servidor.sendmail(user, [para], corpo.as_string()) 

一切，除了主題的一部分確定。 當我嘗試發送一個字符串包含特殊字符（如「動作類」），它提出了這樣的錯誤：

UnicodeEncodeError: 'ascii' codec can't encode characters in position 1-2: ordinal not in range(128) 

我怎麼能MimeText用於中的主題發送電子郵件有特殊字符？

Answer 1

看來，在python3，需要Header對象編碼Subject爲 「UTF-8」：

>>> from email.mime.text import MIMEText 
>>> from email.header import Header 
>>> s = 'ação' 
>>> m = MIMEText(s.encode('utf-8'), 'plain', 'utf-8') 
>>> m['Subject'] = Header(s, 'utf-8') 
>>> m.as_string() 
'Content-Type: text/plain; charset="utf-8"\nMIME-Version: 1.0\nContent-Transfer-Encoding: base64\nSubject: =?utf-8?b?YcOnw6Nv?=\n\nYcOnw6Nv\n' 

所以原來的腳本將變成：

servidor = smtplib.SMTP() 
servidor.connect(HOST, PORT) 
servidor.login(user, usenha) 
assunto = str(self.lineEdit.text()) 
para = str(globe_email)    
texto = str(self.textEdit.toPlainText()) 
corpo = MIMEText(texto.encode('utf-8'), 'plain', 'utf-8') 
corpo['From'] = user 
corpo['To'] = para 
corpo['Subject'] = Header(assunto, 'utf-8') 
servidor.sendmail(user, [para], corpo.as_string())