爲什麼我不斷得到這個被詛咒的SQL * Plus無效標識符錯誤？

Question

我不斷收到一個無效的異常，當我嘗試運行以下腳本： javax.servlet.ServletException：值java.sql.SQLException：[甲骨文] [ODBC] [奧拉] ORA-00904： 「CUSTID」：無效的標識符

Class.forName("sun.jdbc.odbc.JdbcOdbcDriver"); 
    conn = DriverManager.getConnection("jdbc:odbc:rreOracle","xxxxxx","xxxxxxxx"); 
    stmt = conn.createStatement(); 
    PreparedStatement preparedStatement; 

     //get parameters from the request 
     String custID=request.getParameter("cust_ID"); 
     String saleID=request.getParameter("sale_ID"); 
     String firstName=request.getParameter("first_Name"); 
     String mInitial=request.getParameter("mI"); 
     String lastName=request.getParameter("last_Name"); 
     String streetName=request.getParameter("street"); 
     String city=request.getParameter("city"); 
     String state=request.getParameter("state"); 
     String zipCode=request.getParameter("zip_Code"); 
     String DOB=request.getParameter("DOB"); 
     String agentID=request.getParameter("agent_ID"); 
     String homePhone=request.getParameter("home_Phone"); 
     String cellPhone=request.getParameter("cell_Phone"); 
     String profession=request.getParameter("profession"); 
     String employer=request.getParameter("employer"); 
     String referrer=request.getParameter("referrer"); 


    preparedStatement = conn.prepareStatement("UPDATE customer" 
+ " SET customer.cust_ID=?, customer.sale_ID=?, customer.first_Name=?, customer.mI=?, customer.last_Name=?, customer.street_Name=?, customer.city=?, customer.state=?, customer.zip_Code=?,customer. DOB=?, customer.agent_ID=?, customer.home_Phone=?, customer.cell_Phone=?, customer.profession=?, customer.employer=?, customer.referrer=?" 
+ " WHERE customer.cust_ID=custID ") ; 

    preparedStatement.setInt(1, Integer.valueOf(custID)); 
    preparedStatement.setInt(2, Integer.valueOf(saleID)); 
    preparedStatement.setString(3, firstName); 
    preparedStatement.setString(4, mInitial); 
    preparedStatement.setString(5, lastName); 
    preparedStatement.setString(6, streetName); 
    preparedStatement.setString(7, city); 
    preparedStatement.setString(8, state); 
    preparedStatement.setString(9, zipCode); 
    preparedStatement.setString(10, DOB); 
    preparedStatement.setInt(11, Integer.valueOf(agentID)); 
    preparedStatement.setString(12, homePhone); 
    preparedStatement.setString(13, cellPhone); 
    preparedStatement.setString(14, profession); 
    preparedStatement.setString(15, employer); 
    preparedStatement.setString(16, referrer); 

    preparedStatement.executeUpdate(); 

Answer 1

你可以嘗試

<%preparedStatement = conn.prepareStatement("UPDATE customer" 
+ " SET customer.cust_ID=?, customer.sale_ID=?, customer.first_Name=?, customer.mI=?, customer.last_Name=?, customer.street_Name=?, customer.city=?, customer.state=?, customer.zip_Code=?,customer. DOB=?, customer.agent_ID=?, customer.home_Phone=?, customer.cell_Phone=?, customer.profession=?, customer.employer=?, customer.referrer=?" 
+ " WHERE customer.cust_ID=?") ;%> 
<%preparedStatement.setString(17, custID);%> 

或

<%preparedStatement = conn.prepareStatement("UPDATE customer" 
+ " SET customer.cust_ID=?, customer.sale_ID=?, customer.first_Name=?, customer.mI=?, customer.last_Name=?, customer.street_Name=?, customer.city=?, customer.state=?, customer.zip_Code=?,customer. DOB=?, customer.agent_ID=?, customer.home_Phone=?, customer.cell_Phone=?, customer.profession=?, customer.employer=?, customer.referrer=?" 
+ " WHERE customer.cust_ID="+custID) ;%> 

希望它能幫助。

Answer 2

在聲明的這一部分，「WHERE customer.cust_ID = custID」oracle正在尋找名爲「custID」的值。

此時，上下文中的變量名稱不相關 - 在SQL中，「where A = B」語句引用「column A == column B」 - 因爲沒有「custID」列表，oracle抱怨。