無法醃scipy.spatial.KDTree對象

Question

我有一個代碼，我建立一棵巨大的樹，我需要保存它以備後用。 不幸的是，似乎我不能泡菜scipy.spatial.KDTree對象。

事實上，當我運行此：

import pickle 
import scipy.spatial 
tree=scipy.spatial.KDTree([[1,2,3]]) 
pickle.dump(tree,open('tree.p','wb')) 

我得到的錯誤：

Traceback (most recent call last): 
    File "<stdin>", line 1, in <module> 
    File "/usr/lib64/python2.7/pickle.py", line 1370, in dump 
    Pickler(file, protocol).dump(obj) 
    File "/usr/lib64/python2.7/pickle.py", line 224, in dump 
    self.save(obj) 
    File "/usr/lib64/python2.7/pickle.py", line 331, in save 
    self.save_reduce(obj=obj, *rv) 
    File "/usr/lib64/python2.7/pickle.py", line 419, in save_reduce 
    save(state) 
    File "/usr/lib64/python2.7/pickle.py", line 286, in save 
    f(self, obj) # Call unbound method with explicit self 
    File "/usr/lib64/python2.7/pickle.py", line 649, in save_dict 
    self._batch_setitems(obj.iteritems()) 
    File "/usr/lib64/python2.7/pickle.py", line 663, in _batch_setitems 
    save(v) 
    File "/usr/lib64/python2.7/pickle.py", line 331, in save 
    self.save_reduce(obj=obj, *rv) 
    File "/usr/lib64/python2.7/pickle.py", line 401, in save_reduce 
    save(args) 
    File "/usr/lib64/python2.7/pickle.py", line 286, in save 
    f(self, obj) # Call unbound method with explicit self 
    File "/usr/lib64/python2.7/pickle.py", line 562, in save_tuple 
    save(element) 
    File "/usr/lib64/python2.7/pickle.py", line 286, in save 
    f(self, obj) # Call unbound method with explicit self 
    File "/usr/lib64/python2.7/pickle.py", line 748, in save_global 
    (obj, module, name))  pickle.PicklingError: Can't pickle <class 'scipy.spatial.kdtree.leafnode'>: it's not found as scipy.spatial.kdtree.leafnode 

鑑於此，有沒有辦法鹹菜呢？或者至少保存一部分可以用來快速重建樹的對象？否則，除了scipy.spatial.KDTree還有其他快速選項嗎？

Answer 1

使用cKDTree代替KDTree如下：

import pickle 
import scipy.spatial 
tree=scipy.spatial.cKDTree([[1,2,3]]) 
pickle.dump(tree,open('tree.p','wb'))