如何在目錄中打開多個文件

Question

我需要在python3中構建一個簡單的腳本，在目錄中打開更多文件，並查看這些文件內部是否爲關鍵字。

所有目錄中的文件是這樣的： 「F * .formatoffile」（*爲休閒號碼保持）

例子：

f9993546.txt 
f10916138.txt 
f6325802.txt 

Obviusly我只需要打開txt文件那些。

在此先感謝！

最終腳本：

import os 

Path = "path of files" 
filelist = os.listdir(Path) 
for x in filelist: 
    if x.endswith(".txt"): 
     try: 
      with open(Path + x, "r", encoding="ascii") as y: 
       for line in y: 
        if "firefox" in line: 
         print ("Found in %s !" % (x)) 
     except: 
      pass 

Answer 1

這應該做的伎倆：

import os 
Path = "path of the txt files" 
filelist = os.listdir(Path) 
for i in filelist: 
    if i.endswith(".txt"): # You could also add "and i.startswith('f') 
     with open(Path + i, 'r') as f: 
      for line in f: 
       # Here you can check (with regex, if, or whatever if the keyword is in the document.)