假設以下班級,您如何找到帶有特定電子郵件地址的Person
?如何寫參數是一組JPA查詢?
public class Person implements Comparable<Person> {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name="id")
private long id = 0;
@OneToMany(cascade={CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REMOVE}, fetch=FetchType.LAZY)
private Set<String> email = new HashSet<String>();
}
就像做這件事一樣簡單,還是有一個合適的方法?
select p from Person p where p.email=:email