在結果中獲得相同的記錄兩次

Question

$ids = array(30,30); 



    $items = (array) $db->getRecords('SELECT i.id 
    ,i.num_persons 
    ,i.rating 
    ,i.lat 
    ,i.lng 
    ,i.street 
    ,i.number 
    ,c.title 
    ,c.introduction 
    ,c.text 
    ,c.area 
    ,c.long_term_rental 
    ,c.beds 
    ,c.features 
    ,c.services_and_equipment 
    ,c.terms_and_conditions 
    ,MIN(p.price) as price 
    ,m.url 
    FROM appartments AS i 
    INNER JOIN appartments_content AS c on c.parent_id = i.id 
    INNER JOIN meta AS m on m.id = c.meta_id 
    INNER JOIN appartments_pricing AS p on p.appartment_id = i.id 
    WHERE c.language = ? AND i.hidden = ? AND i.publish_on <= ? AND i.id IN('. implode(',', $ids) .') 
    GROUP BY i.id', 
    array(FRONTEND_LANGUAGE, 'N', FrontendModel::getUTCDate('Y-m-d H:i') . ':00')); 

如何在結果集中兩次（或多次）獲取相同的記錄？

Answer 1

這並不是說很漂亮，但是....

$nestedIds = "select 1 as id union all select 1 union all select 2"; 

'select i.id, i.num_persons, i.rating, i.lat, i.lng, i.street, i.number, 
i.title, i.introduction, i.text, i.area, i.long_term_rental, i.beds, i.features, 
i.services_and_equipment, i.terms_and_conditions, i.price, i.url 
from 
('.$nestedIds.') as un 
inner join 
( 
SELECT i.id, i.num_persons, i.rating, i.lat, i.lng, i.street, i.number, 
c.title, c.introduction, c.text, c.area, c.long_term_rental, c.beds, c.features, 
c.services_and_equipment, c.terms_and_conditions, MIN(p.price) as price, m.url 
FROM appartments AS i 
INNER JOIN appartments_content AS c on c.parent_id = i.id 
INNER JOIN meta AS m on m.id = c.meta_id 
INNER JOIN appartments_pricing AS p on p.appartment_id = i.id 
INNER JOIN as un on un.id = i.id 
WHERE c.language = ? AND i.hidden = ? AND i.publish_on <= ? AND i.id IN (1,1,2) 
GROUP BY i.id 
) as i 
on i.id = un.id;' 

我用ID 1（兩次）和id 2作爲用於說明的實例。我想你必須以編程方式建立「un」嵌套表的列表。

或者，您可以在查詢之外處理它。

希望它有幫助！

Tom