做graph.run()這是我創建從一個txt文件的圖形py2neo代碼: import csv
import re
from py2neo import Graph,Node,Relationship
graph = Graph("http://localhost:7474/browser/")
with open("<>") as infile:
row_num = 0
在py2neo V2.0,這是可以使用的交易執行Cypher支架聲明: tx=graph.cypher.begin()
tx.append("MERGE (n:Process {proc_nm : {proc_nm}}) ON CREATE SET n.count = 1 ON MATCH SET n.count = n.count +1", {proc_nm : 'wibble'})
tx.
單查詢節點列表之間的最短路徑,我有兩個列表 ['avia', 'paul', 'tom']
['james','bond']
我特林找到 avia -> james
paul -> james
tom -> james
avia -> bond
paul -> bond
tom -> bond
我創建查詢,在兩個循環之間的shortes路徑每次查詢neo4j 因此對neo4j
我想用這個來讀取一個JSON文件的屬性: d['text']['entities']['mention'][0]['screen_name'] JSON文件 {
"text" : {
"content" : "@narendramodi Did u even know the fare of metro has been increased by 65%",
"