嗨,我有一個表「狀態」與2列id和string。 我插入一個數據,例如id = 1和string = {"1": "Enable", "2": " Disabled"}。 我該如何才能在SQL中獲得值「Enable」? If I type SELECT
id, string->"$.1"
FROM status;
我有無效的JSON路徑表達式。
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任何人都可以請幫我改變fpdf中的圖像目錄嗎? 我需要從保存數據庫的圖像中獲取圖像,因爲我的客戶給了我圖像。我正在使用laravel 5.4。從數據庫 ****
But FPDF is searching for image in fpdf folder.
I want to change directory to the saved folder.
//擷取標誌 $pdf->Image(