鑑於下面的代碼片斷: #include <stdio.h>
typedef signed long long int64;
typedef signed int int32;
typedef signed char int8;
int main()
{
printf("%i\n", sizeof(int8));
printf("%i\n", sizeof(int3
下面是一個查詢,我發現在MySQL,以顯示我的錯誤和警告: SELECT
`DIGEST_TEXT` AS `query`,
`SCHEMA_NAME` AS `db`,
`COUNT_STAR` AS `exec_count`,
`SUM_ERRORS` AS `errors`,
(ifnull((`SUM_ERRORS`/nullif(`COUNT_STAR`,0)),0) * 10
我有一個可能包含重複的數據集。爲了找到數據集中,我把指數爲numpy的結構陣列的複製,排序的陣列,從唯一值創建另一個數組,然後比較兩個數組的長度: data = np.zeros(t_len, dtype={'names':['date', 'symbol'], 'formats':['i8', 'S16']})
data[:] = [(x['date'], x['symbol']) for x