我知道答案常問How do I specify a pointer to an overloaded function?：要麼與轉讓或與演員陣容，和所有其他的C++教程轉換爲大寫像這樣的字符串（給予或採取static_cast）： transform(in.begin(), in.end(), back_inserter(out), (int(*)(int)) std::toupper);
或
考慮下面的F＃代碼： [<Measure>] type pixel
[<Measure>] type inch
[<Measure>] type dot
[<Measure>] type percentage
let scaleCalculation (finalSize:float<pixel>) (originalSize:float<pixel>) =
finalSize
可能重複： Why can't my C++ compiler deduce template argument for boost function? Isn't the template argument (the signature) of std::function part of its type? 我有以下幾點： #include <functional>
void Foo(std
考慮代碼 public class Base
{
public virtual int Add(int a,int b)
{
return a+b;
}
}
public class Derived:Base
{
public override int Add(int a,int b)
{
return a+b;
我正在通過一些關於C＃4.0的演示文稿，最後演示者用以下代碼發佈了測驗。 using System;
class Base {
public virtual void Foo(int x = 4, int y = 5) {
Console.WriteLine("B x:{0}, y:{1}", x, y);
}
}
class Derived : Ba