這裏是尋找代碼,如果給定的二叉樹是二叉搜索樹(BST)或不: bool isBST(struct node* root)
{
// traverse the tree in inorder fashion and keep track of prev node
if (root)
{
struct node *prev = NULL;
if
對於二叉搜索樹(不一定是平衡BST),我有兩個獨立的getHeight()方法實現,一個是迭代的,一個是遞歸的。這裏的迭代之一: def height(root): #iterative approach, uses a stack for a depth first search
max_height = 0
myStack = [root]
currentNode
我試圖實現紅黑樹數據結構,並遇到來自Apple Open Source項目的this示例。這是創建樹的代碼:我想知道什麼是具有前哨淋巴結而不是孩子指着NULL背後的推理 /*
* Create a red black tree struct using the specified compare routine.
* Allocates and returns the initialized
二叉搜索樹錯誤 /* These are struct definitions I am using */
struct PdsNdxInfo{
int key;
int offset;
};
struct PdsInfo{
FILE *repo_fptr;
FILE *ndx_fptr;
char repo_name[MAX_NAME_L