mysql相關查詢

Question

我需要編寫一個查詢，我需要從表中檢索數據。

Table 
=================================== 
ID | userID | Status | date | 
=================================== 
1  3333  Queued xxxx 
2  4444  Queued yyyy 
3  5555  Finished zzzzz 
5  6666  Queued iiiii 
6  7777  Queued kkkkk 

現在我只想檢索如果狀態=「排隊」，並與狀態=「排隊」行均超過2行，並用最新的ID行。即我想要的答案是ID = 6

我試着用下面的查詢

select * from t1 where status = "Queued" GROUP BY status HAVING count(status) > 2 ORDER BY ID DESC limit 1 

Answer 1

你可以使用子查詢了點。問題在於排序是在分組之前完成的。像這樣的東西應該工作：

select * from t1 where ID = (select max(id) from t1 where status = "Queued" group by status having count(status) > 2) 

Answer 2

以下查詢應該解決這個問題：

select * from t1 
where id = (select max(id) from t1 where Status = 'Queued' group by Status having count(1)>2); 

Answer 3

這變化也是可能的 -

SELECT * FROM (
    SELECT * FROM t1 WHERE status = 'Queued' ORDER BY ID DESC) t 
GROUP BY status HAVING count(status) > 2;