如何在SQL中對我的列進行分組？

Question

如何按時間分組？我想這一點，但它給錯誤「無效列名‘時間’。」：

select Count(Page) as VisitingCount, CONVERT(VARCHAR(5), Date, 108) as [Time] 
from scr_SecuristLog 
where Date between '2009-05-04 00:00:00' and '2009-05-06 14:58' 
and [user] in (select USERNAME from scr_CustomerAuthorities) 
group by [Time] order by [VisitingCount] asc 

Answer 1

[時間]是一個列別名。嘗試

SELECT 
     COUNT(Page) AS VisitingCount 
    , CONVERT(VARCHAR(5),Date, 108) AS [Time] 
FROM 
    scr_SecuristLog 
WHERE 
    Date BETWEEN '2009-05-04 00:00:00' AND '2009-05-06 14:58' 
    AND 
    [user] IN (
       SELECT 
        USERNAME    
       FROM 
        scr_CustomerAuthorities 
       ) 
GROUP BY 
    CONVERT(VARCHAR(5),Date, 108) 
ORDER BY 
    [VisitingCount] ASC 

Answer 2

嘗試

GROUP BY CONVERT(VARCHAR(5),Date, 108) 

始終在您的SELECT子句確保你按的一切，沒有一個它的聚合函數。

Answer 3

select Count(Page) as VisitingCount,CONVERT(VARCHAR(5),Date, 108) as [Time] from scr_SecuristLog 
where Date between '2009-05-04 00:00:00' and '2009-05-06 14:58' 
and [user] in(select USERNAME    
    from scr_CustomerAuthorities) 
group by CONVERT(VARCHAR(5),Date, 108) order by [VisitingCount] asc 

我修改GROUP BY以包括用於[Time]實際表達，而不是列的別名（因爲這不能在GROUP BY可以使用，只有ORDER BY）

Answer 4

看起來像日期是這裏的一列，但它是一個關鍵字，沒有引用。也許這是個問題（不是雖然測試）：

select Count(Page) as VisitingCount,CONVERT(VARCHAR(5),[Date], 108) as [Time] from scr_SecuristLog 
where [Date] between '2009-05-04 00:00:00' and '2009-05-06 14:58' 
and [user] in(select USERNAME    
    from scr_CustomerAuthorities) 
group by [Time] order by [VisitingCount] asc 

Answer 5

如果你不想重複日期轉換（有時計算是有點比簡單的轉換更密集），那麼你可以使用這樣的事情：

select * 
from (select Count(page) .., ... As [Date] from ... where ...) UG 
group by UG.[Date] 

請注意，您有帶來的「UG」名內部選擇，並認爲這將是最有可能的，而且在大多數情況下比原分組重複轉換表達效率較低。 你的整個表情很可能會改變......但是，只是你知道這是可能的。