彈簧安置控制器：如何避免與相同RequestParams

Question

在彈簧安置控制器類的方法，有三種方法具有相同@RequestParams，但不同RequestMappings和行爲，如在下面的（簡化的）例子：

@RequestMapping(method = GET, value = "/search") 
    public MySearchResponse findAll(
      @RequestParam(required = false, value = "foo") String foo, 
      @RequestParam(required = false, value = "bar") String bar, 
      @RequestParam(required = false, value = "baz") Long baz, 
      @RequestParam(required = false, value = "fooBar") Long fooBar 
    ) { ...} 

@RequestMapping(method = GET, value = "/export") 
    public MyExportResponse exportAll(
      @RequestParam(required = false, value = "foo") String foo, 
      @RequestParam(required = false, value = "bar") String bar, 
      @RequestParam(required = false, value = "baz") Long baz, 
      @RequestParam(required = false, value = "fooBar") Long fooBar 
    ) { ...} 

有沒有辦法避免@ RequestParam的代碼重複？

Answer 1

將它們替換爲單個對象。

static class MyParmeters { 
    String foo; 
    String bar; 
    Long baz; 
    Long fooBar; 
} 

@RequestMapping(method = GET, value = "/search") 
public MySearchResponse findAll(MyParmeters params) { ... } 

@RequestMapping(method = GET, value = "/export") 
public MyExportResponse exportAll(MyParameters params) { ... } 

另請參閱How to bind @RequestParam to object in Spring MVC。

Answer 2

您可以定義一個名爲MyResponse父類型，然後你可以使用ResponseEntity，如下圖所示：如下圖所示

@RequestMapping(method = GET, value = "/searchOrExport") 
public ResponseEntity<MyResponse> exportAll(@RequestParam(required = false, value = "foo") String foo, 
      @RequestParam(required = false, value = "bar") String bar, 
      @RequestParam(required = false, value = "baz") Long baz, 
      @RequestParam(required = false, value = "fooBar") Long fooBar) { 
     //code to handle search and Export 
} 

Bean類API：

public abstract class MyResponse { 
    //any common properties add here 
} 


public class MySearchResponse implements MyResponse { 
    //add MySearchResponse properties 
} 

public class MyExportResponse implements MyResponse { 
    //add MyExportResponse properties 
}