的preg_replace沒有忽視[]從字符串

Question

這是我的代碼：

$string = "Hello this is my text [readmore] and this is remaining text"; 
echo preg_replace("[readmore]","",$string); 

這是我預期輸出：

Hello this is my text and this is remaining text 

這是我實際輸出：

Hello this is my text [] and this is remaining text 

問題很簡單如何獲得乘坐「[]」也是？

Answer 1

您需要逃生[ & ]。嘗試下面的正則表達式，

preg_replace("/\[([^\[\]]++|(?R))*+\]/", "", $string); 

OUTPUT：

Hello this is my text and this is remaining text 

CodePad Demo.

Answer 2

您需要轉義括號才能在正則表達式中使用。另外，您可能需要查看preg_replace的手冊，因爲您忘記了/需要圍繞您的正則表達式。

$string = "Hello this is my text [readmore] and this is remaining text"; 
echo preg_replace("/\[readmore\]/","",$string); 

Answer 3

逃離 '[' 和 ']' 字符：

這個腳本：

$string = "Hello this is my text [readmore] and this is remaining text"; 
echo preg_replace("[\\[readmore\\] ]","",$string); 

這個結果（我測試了這一點）：

Hello this is my text and this is remaining text  

Answer 4

使用str_replace

$string = "Hello this is my text [readmore] and this is remaining text"; 
echo str_replace("[readmore]","",$string); 

輸出

Hello this is my text and this is remaining text