你可以這樣做:
SELECT * FROM PART_TABLE
WHERE REPLACE(REPLACE(PARTNO,'/', ''),'-','') LIKE '%D12A%'
這會爲你工作指定的2個字符,並可以擴展爲多個字符,像這樣:
SELECT * FROM PART_TABLE
WHERE REPLACE(REPLACE(REPLACE(PARTNO,'/', ''),'-',''),*,'') LIKE '%D12A%'
也許不是最優雅的解決方案除非你的特殊字符有限。否則,我會建議編寫一個函數來去除非字母數字字符。
這裏是這樣的功能的例子:取自
CREATE FUNCTION dbo.udf_AlphaNumericChars
(
@String VARCHAR(MAX)
)
RETURNS VARCHAR(MAX)
AS
BEGIN
DECLARE @RemovingCharIndex INT
SET @RemovingCharIndex = PATINDEX('%[^0-9A-Za-z]%',@String)
WHILE @RemovingCharIndex > 0
BEGIN
SET @String = STUFF(@String,@RemovingCharIndex,1,'')
@RemovingCharIndex = PATINDEX('%[^0-9A-Za-z]%',@String)
END
RETURN @String
END
------- Query Sample (untested)---------
SELECT *
FROM PART_TABLE
WHERE DBO.udf_AlphaNumericChars(PARTNO) LIKE '%D12A%'
:http://sqlserver20.blogspot.co.uk/2012/06/find-alphanumeric-characters-only-from.html