當用戶點擊<a>
標籤時,如何將PersonID的值發送到edit.php?如何將php的值發送給ajax?
<?php
$result = mysql_query("SELECT PersonID, FirstName, LastName, Age FROM persons");
echo "<table>";
while ($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>Name: ".$row['FirstName']." ".$row['LastName'].", Age: ".$row['Age']."</td>";
?>
<td>
<a class="edit" name="<?php echo $row['PersonID'] ?>">Edit</a>
</td>
<?php
echo "</tr>";
}
echo "</table>";
?>
這裏的unfinish AJAX,
<script type="text/javascript" language="javascript">
$("a.edit").click(function(){
$(this).closest("tr").after("<div id=\"editform\"></div>");
$.ajax({
url: "edit.php",
// -- WHAT SHOULD BE THE NEXT STEP? --
});
});
</script>
謝謝!