我有一個SQLite數據庫,有四個名爲餐廳,酒吧,景點和住宿的表。每個表都有3列,分別命名爲id,名稱和說明。我試圖從一個JSON文件看起來像這樣用數據填充數據庫:使用JSON數據填充SQLite表,得到:sqlite3.OperationalError:接近「x」:語法錯誤
{
"restaurants": [
{"id": "ChIJ8xR18JUn5IgRfwJJByM-quU", "name": "Columbia", "description": "Traditional Spanish restaurant, a branch of a long-standing local chain dating back to 1905."},
],
"bars": [
{"id": "ChIJ8aLBaJYn5IgR60p2CS_RHIw", "name": "Harrys", "description": "Chain outpost serving up Creole dishes in a leafy courtyard or on a balcony overlooking the bay."},
],
"attractions": [
{"id": "ChIJvRwErpUn5IgRaFNPl9Lv0eY", "name": "Flagler", "description": "Flagler College was founded in 1968. Formerly one of Henry Flagler's hotels, the college is allegedly home to many spirits. Tours are offered"},
],
"lodging": [
{"id": "ChIJz8NmD5Yn5IgRfgnWL-djaSM", "name": "Hemingway", "description": "Cottage-style B&B offering a gourmet breakfast & 6 rooms with private baths & traditional decor."},
]
}
每當腳本試圖執行查詢時,我得到sqlite3.OperationalError: near "x": syntax error
,其中x是從描述中的一個隨機字。示例錯誤如下所示:sqlite3.OperationalError: near "Spanish": syntax error
。這個詞並不總是西班牙文,但它總是一個描述中的一個詞。
我已經嘗試了幾種不同的方法,但總是得到相同的結果,這裏是一個方法我都試過:
import sqlite3
import json
places = json.load(open('locations.json'))
db = sqlite3.connect('data.db')
for place, data in places.items():
table = place
for detail in data:
query = 'INSERT OR IGNORE INTO ' + place + ' VALUES (?, ?, ?), (' \
+ detail['id'] + ',' + detail['name'] + ',' + detail['description'] + ')'
c = db.cursor()
c.execute(query)
c.close()
而且我也嘗試寫這樣的查詢:
query = 'INSERT OR IGNORE INTO {} VALUES ({}, {}, {})'\
.format(table, detail['id'], detail['name'], detail['description'])
感謝您的快速響應。我很確定這是我讀過的問題,不幸的是,當我嘗試你的方法時,我得到了'c.execute(query,(detail ['id'],detail ['name'],detail ['description']] ))sqlite3.IntegrityError:datatype mismatch' –
@GrantJordan啊,好吧,如果你在表名後面明確指定了列名,會發生什麼,例如'INSERT或IGNORE INTO {}(COLUMN1,COLUMN2,COLUMN3)VALUES(?,?,?)' – alecxe
好吧,數據類型不匹配錯誤是因爲我將id列設置爲Integer而不是Text,而我的id是字母數字。感謝您的幫助,腳本現在運行無誤! –