即時得到的JSON響應到我的應用[Twitter的web服務],是一個字符串,但是,例如索引0處的對象是:IOS陣列到字典或陣列
es array en:0, tiene {
contributors = "<null>";
coordinates = "<null>";
"created_at" = "Thu Aug 04 23:26:05 +0000 2011";
favorited = 0;
geo = "<null>";
id = 99259843982016513;
"id_str" = 99259843982016513;
"in_reply_to_screen_name" = "<null>";
"in_reply_to_status_id" = "<null>";
"in_reply_to_status_id_str" = "<null>";
"in_reply_to_user_id" = "<null>";
"in_reply_to_user_id_str" = "<null>";
place = "<null>";
"possibly_sensitive" = 0;
"retweet_count" = 0;
retweeted = 0;
source = "<a href=\"http://twitter.com/tweetbutton\" rel=\"nofollow\">Tweet Button</a>";
text = "Stack Exchange Q&A site proposal: Freelance Workers http://t.co/yaW1RHp";
truncated = 0;
user = {
"contributors_enabled" = 0;
"created_at" = "Mon Jul 13 19:39:31 +0000 2009";
"default_profile" = 0;
"default_profile_image" = 0;
description = "My goal is to enable the brain computer interfaces to use the possibilities of mobile platforms for robotics and physical computing";
"favourites_count" = 0;
"follow_request_sent" = "<null>";
"followers_count" = 92; ...
所以有像17我的數組[對於每個twitt]的對象,那麼如何將這些對象分解爲更多的數組或字典?
我specifaclly想要的文字鍵
text = "Apple vs Samsung tablets [haha and Samsung is an Apple hardware provider!!]\nhttp://t.co/rvv43Hy";
非常感謝
(第一個)「text」值很容易,因爲它位於外部字典中。只需使用'objectForKey:@「文本」'。 (但是你爲「文本」顯示了不同的值,因此它可能是更深入的嵌入版本。) –