我對Commons VFS有問題。我想要使用SFTP連接到一個目錄並列出它。下面是代碼:Commons VFS - 無法列出目錄的內容
FileSystemOptions opts = new FileSystemOptions();
SftpFileSystemConfigBuilder.getInstance().setStrictHostKeyChecking(opts, "no");
FileSystemManager fsManager = VFS.getManager();
FileObject sourceDir = fsManager.resolveFile(sourceUrl, opts);
FileObject targetDir = fsManager.resolveFile(config.get("to"));
for (FileObject sourceFile : sourceDir.getChildren()) { // here is the problem
FileObject targetFile = fsManager.resolveFile(targetDir + "/" + nodeName + "_"
+ sourceFile.getName().getBaseName());
logger.debug("Copying files. Source: " + sourceFile.getName().getPath() + " Target: "
+ targetFile.getName().getPath());
}
看來,fsManager
解析正確,但getChildren()
失敗。我發現sourceDir
是一個IMAGINARY
類型;下面的代碼說它
logger.debug(sourceDir.getType());
我檢查了文件,它是一個普通的文件夾 - 不是一個鏈接或類似的東西。
錯誤
org.apache.commons.vfs2.FileNotFolderException: Could not list the contents of "sftp://path/to/dir" because it is not a folder.
at org.apache.commons.vfs2.provider.AbstractFileObject.getChildren(AbstractFileObject.java:693)
at pkg.services.impl.QuartzJobEventLog.downloadEventLogs(QuartzJobEventLog.java:64)
at pkg.services.impl.QuartzJobEventLog.executeJob(QuartzJobEventLog.java:37)
at pkg.services.impl.AbstractQuartzJob.execute(AbstractQuartzJob.java:25)
at $QuartzJob_1360635dbcd.execute($QuartzJob_1360635dbcd.java)
at org.quartz.core.JobRunShell.run(JobRunShell.java:203)
at org.quartz.simpl.SimpleThreadPool$WorkerThread.run(SimpleThreadPool.java:520)
見@最多的回答。 – hotshot309 2013-11-19 17:39:13