獲取最後一個副本

我的問題是，因爲人們對我們的運輸訂單犯了錯誤，並且創建了另一個追蹤＃來修正訂單，因此存在欺詐行爲。所以我總是需要得到訂單的最後一個副本，所以我得到正確的跟蹤＃。獲取最後一個副本

我已經試過這樣：

SELECT OrderNum, TrackingNumber, CreatedDate, CreatedBy, Carrier 
FROM FPDWDB1.Ship.dbo.ShippingLog 
GROUP BY OrderNum

我收到以下錯誤：

Column 'FPDWDB1.Ship.dbo.ShippingLog.TrackingNumber' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.

來源

2016-06-14 Chris Rosenau

如果使用GROUP BY，所有其他列以外該組需要被用在一個聚合函數中，即max，avg等等。它聽起來像像你需要一個row_number（），它是決定最新記錄的CreatedDate？ – artm

Select OrderNum, TrackingNumber, CreatedDate, CreatedBy, Carrier 
FROM (
SELECT OrderNum, TrackingNumber, CreatedDate, CreatedBy, Carrier 
     ,ROW_NUMBER() OVER (PARTITION BY OrderNum ORDER BY CreatedDate DESC) rn 
FROM FPDWDB1.Ship.dbo.ShippingLog 
) A Where rn = 1

WITH A AS (
SELECT OrderNum, TrackingNumber, CreatedDate, CreatedBy, Carrier 
     ,ROW_NUMBER() OVER (PARTITION BY OrderNum ORDER BY CreatedDate DESC) rn 
FROM FPDWDB1.Ship.dbo.ShippingLog 
) 
Select OrderNum, TrackingNumber, CreatedDate, CreatedBy, Carrier 
FROM A 
Where rn = 1

來源

2016-06-15 00:36:17

獲取最後一個副本

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