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是否有任何人能夠從我所基於的截圖和模型建立的雄辯關係建議? Laravel 5.1雄辯關係
模型設置:
class Leaves extends Model
{
protected $table = 'leaves';
protected $fillable = [
'leave_type',
'user_id'
];
public function user()
{
return $this->belongsTo('App\User');
}
}
class LeaveType extends Model
{
protected $table = 'leave_type';
protected $fillable = ['type_name'];
}
class User extends Model implements AuthenticatableContract,
AuthorizableContract,
CanResetPasswordContract
{
use Authenticatable, Authorizable, CanResetPassword;
protected $table = 'users';
protected $fillable = ['name', 'email', 'password'];
protected $hidden = ['password', 'remember_token'];
public function leave()
{
return $this->hasMany('App\Leaves');
}
}
目前我只能讓葉細節,但需要根據
$user = User::oldest('name')->get();
foreach ($users as $user) {
$user->leave()-get();
}
還注意到' - > leave'和' - > type'在獲取屬性時缺少'()'。 '休假()'會返回一個查詢生成器,所以你可以做'$用戶>離開() - >創建($假);' –
我似乎對功能型)問題( 有什麼毛病我外鍵引用?從附件中,Leaves表中的leave_type是對leave_type表的外部引用 – Derrick
我錯過了,對不起,laravel的默認值是'model_name_id'。在你的情況下,這將是'leave_type_id',但你可以覆蓋它。語法是'return $ this-> hasOne('App \ Model_Name','foreign_key','local_key');' –