C＃中的小數點＃

Question

對於C＃來說相當新穎。我有以下代碼來計算兩點之間的距離和角度。然而，它不會顯示小數點（需要小數點後三位，我認爲浮點數據類型可以處理十進制數字嗎？

例如，點1 x = 2，點1 y = 2，點2 x = 1，點2 y = 1。

距離計算爲1，角度計算爲-1距離應該是1.414 &角度應該是-135.000度，所以它就像它將它們向上/向下四捨五入感...

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Threading.Tasks; 

namespace AngleDistanceCalc 
{ 
    class Program 
    { 
     static void Main(string[] args) 
     { 
      // print welcome message 
      Console.WriteLine("Welcome. This application will calculate the distance between two points and display the angle."); 

      Console.WriteLine("Please enter point 1 X value:"); 
      float point1X = float.Parse(Console.ReadLine()); 

      Console.WriteLine("Please enter point 1 Y value:"); 
      float point1Y = float.Parse(Console.ReadLine()); 

      Console.WriteLine("Please enter point 2 X value:"); 
      float point2X = float.Parse(Console.ReadLine()); 

      Console.WriteLine("Please enter point 2 y value:"); 
      float point2Y = float.Parse(Console.ReadLine()); 

      float deltaX = point2X - point1X; 
      float deltaY = point2Y - point2X; 

      double distance = Math.Sqrt(deltaX * deltaX + deltaY * deltaY); 

      Console.WriteLine("The distance between the points is: {0}", distance); 

      Console.WriteLine("The angle between the points is: {0}", deltaX); 
     } 
    } 
} 

Answer 1

float deltaY = point2Y - point2X; 

你必須在ab中的錯誤ove線。你需要計算：

float deltaY = point2Y - point1Y; 

此外，你需要引入計算角度的邏輯。該公式在this answer下討論：

var angle = Math.Atan2(deltaY, deltaX) * 180/Math.PI; 
Console.WriteLine("The angle between the points is: {0}", angle);