如何使用處理程序在後臺運行任務

我正在使用以下代碼來訪問Web服務，並向我顯示錯誤應用程序沒有響應。如何使用處理程序在後臺運行任務

package com.android.webservice; 

import org.ksoap2.SoapEnvelope; 
import org.ksoap2.serialization.SoapObject; 
import org.ksoap2.serialization.SoapSerializationEnvelope; 
import org.ksoap2.transport.HttpTransportSE; 

import android.app.Activity; 
import android.os.Bundle; 
import android.view.View; 
import android.view.View.OnClickListener; 
import android.widget.Button; 
import android.widget.EditText; 
import android.widget.TextView; 
import android.widget.Toast; 

public class WebServiceActivity extends Activity { 
    private static final String SOAP_ACTION = "http://tempuri.org/HelloWorld"; 

    private static final String METHOD_NAME = "HelloWorld"; 

    private static final String NAMESPACE = "http://tempuri.org/"; 
    private static final String URL = "http://192.168.1.19/TestWeb/WebService.asmx"; 


    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.main); 



     Button getquote = (Button) findViewById(R.id.getquote); 
     getquote.setOnClickListener(new OnClickListener() { 

     public void onClick(View v) { 
      TextView result1; 
      result1=(TextView)findViewById(R.id.result1); 
     try { 


      SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); 
      EditText CompanyName = (EditText) findViewById(R.id.CompanyName); 
      String val1 = (CompanyName.getText().toString()); 
      request.addProperty("passonString", val1); 

      SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
      envelope.dotNet=true; 
      envelope.setOutputSoapObject(request); 

      HttpTransportSE androidHttpTransport = new HttpTransportSE(URL); 
      androidHttpTransport.call(SOAP_ACTION, envelope); 

      Object result = (Object)envelope.getResponse(); 

      result1.setText(result.toString()); 
     } catch (Exception e) { 

      result1.setText(e.getMessage()); 
      } 
    } 
}); 
    } 
}

可能是因爲這是在UI線程中運行，我想用處理程序後臺運行它，我在這個領域很新，所以有poroblem把它寫在後臺線程。任何人都可以請給我指示，如何編寫處理程序內的代碼。謝謝

來源

2011-09-30 Ritu

試試這個:: AsyncTask使適當和簡單的使用UI線程。該類允許執行後臺操作並在UI線程上發佈結果，而無需操縱線程和/或處理程序。

異步任務由在後臺線程上運行並且其結果在UI線程上發佈的計算定義。異步任務是由3種一般類型，稱爲PARAMS，進展和結果，以及4個步驟所定義，稱爲onPreExecute，doInBackground，onProgressUpdate和onPostExecute

 private class xyz extends AsyncTask<Void, Void, Void> { 
    private final ProgressDialog dialog = new ProgressDialog(tranning.this); 

    @Override 
    protected void onPreExecute() { 
     this.dialog.setMessage("Please Wait..."); 
     this.dialog.show(); 
     // put your code which preload with processDialog 
    } 


    @Override 
    protected Void doInBackground(Void... arg0) { 
     // put your code here 
     return null; 
    } 

    @Override 
    protected void onPostExecute(final Void unused) { 
     if (this.dialog.isShowing()) { 
      this.dialog.dismiss(); 

     } 
    } 
}

和在主::使用此