如何爲PHP循環中創建的按鈕創建函數？

Question

while($record = mysql_fetch_array($myData)){ 
if(($record['Opponent'] == "") && ($record['better_name'] != $_SESSION['user_name'])){ 

    $acceptID = "accept" . $record['bet_ID']; 
    echo "<form action=index.php method=post>"; 
    echo "<input type=submit name=" . $acceptID . " value="ACCEPT">"; 
    echo "<input type=hidden id=" . $record['bet_ID'] . ">"; 
    echo "</form>"; 
} elseif (($record['Opponent'] == "") && ($record['better_name'] == $_SESSION['user_name'])){ 
    echo "<form action=index.php method=post>"; 
    echo "<input type=submit name=delete value=DELETE>"; 
    echo "<input type=hidden id=" . $record['bet_ID'] . ">"; 
    echo "</form>"; 
} else { 
    echo "Game Locked."; 

Answer 1

我試圖通過$_POST['ACCEPT']和$_POST['DELETE']命令傳遞bet_ID。原來，我不需要每個輸入/按鈕的表單。這對我來說很有效：

## $record['bet_ID'] was pulled from an SQL database table. 


echo "<input type=hidden name=accept value='$record[bet_ID]'>"; 
echo "<input type=submit value=Accept>"; 

$date = $_POST['accept']; 
echo $date;