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我編碼,我這裏得到一個錯誤:這個lua編碼有什麼問題?
Ammo = 450
Rocket = 20
Money = 35041
--Can I attend this mission?
function attendMission()
if Ammo >= 400 or Rocket >= 35 and Money >= 30000 then
return Money = Money - 30000
Msg("Attending Mission\n")
Msg("You now have "..Money.." dollars\n")
else
Msg("You do not have the resources to attend this mission\n")
end
end
print(attendMission())
--Ammo Amount
function whatIsAmmo()
if Ammo > 0 then
print("You have "..Ammo.." Ammo")
else
Msg("You have no Ammo")
end
end
print(whatIsAmmo())
--Rocket Amount
function whatIsRocket()
if Rocket > 0 then
Msg("You have "..Rocket.." rockets")
else
Msg("You have no rockets")
end
end
print(whatIsRocket())
--Money Amount
function whatIsMoney()
if Money > 100000 then
Msg("You have "..Money.." dollars, wow your rich!")
elseif Money > 0 then
Msg("You have "..Money.." dollars")
else
Msg("You have no money")
end
end
print(whatIsMoney())
它說,有預計近期=結束。我一直在尋找一段時間,但我不知道如何解決它。我已經縮小了錯誤在這一部分,雖然:
function attendMission()
if Ammo >= 400 or Rocket >= 35 and Money >= 30000 then
return Money = Money - 30000
Msg("Attending Mission\n")
Msg("You now have "..Money.." dollars\n")
else
Msg("You do not have the resources to attend this mission\n")
end
end
在Lua中(與C和其他一些語言不同),賦值是一個語句,而不是表達式。 – 2014-12-11 00:58:53
好吧,我這樣做了,但是現在我在'Msg'附近得到''end''(如果'在6號線關閉')' – laws16 2014-12-11 00:59:52
'return'也需要是塊中的最後一個語句(至少在lua中5.1)。所以這必須是該區塊的最後一行。儘管你可以使用'do return end'來強制一個塊使其工作。 – 2014-12-11 01:00:25