使從使用python

Question

兩個文件我有以下兩個文件存在/不存在基質：

的（a）：

A01 
A02 
A03 
A10 
A11 
C03 
C10 
C11 
E01 
E10 
E11 
H01 
H02 
H10 
H11 
Y09 
Y10 
Y11 

和

（B）：

E01 Y09 A02 
A01 A03 
C03 H01 H02 
E10 
Y10 
A10 
C10 
H10 
E11 A11 C11 H11 Y11 

我試圖從這個數據中做出一個存在/不存在的矩陣，以查看（a）中的值是否存在於（b）中的行中。如果它們存在，那麼它們應該用「1」表示，否則應該用「0」表示，其中「0」和「1」指示符跟隨（a）中的值的序列。

我的預期輸出是：

0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 
1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 1 0 0 0 0 0 1 1 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 
0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 
0 0 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 

我曾嘗試以下：

text_file = open("Table", "w") 
a = file("list", "r") 
b = file("cluster", "r") 

for line in a: 
    words = line.split("\n") 
for line in b: 
    words = line.split("\t") 


for line in a: 
    if words in a == words in b: 
     print("1") 
    elif words in a != words in b: 
     print("0") 
text_file.close 

然而，這並不顯示任何信息。

任何人都可以幫忙嗎？

Answer 1

這產生從兩個輸入文件所要求的輸出：

with open('list', 'rt') as list_file: 
    values = [line.strip() for line in list_file] 

with open('cluster', 'rt') as cluster_file, open('Table', 'wt') as table_file: 
    for cluster in (set(line.split()) for line in cluster_file): 
     row = ' '.join('01'[value in cluster] for value in values) 
     table_file.write(row + '\n') 

Answer 2

我想我明白你想在這裏。

final_matrix = [] 
a = file("list", "r") 
a_list = [] 
# Make a list of all strings in the first file. 
for line in a: 
    a_list.append(line.rstrip()) 

b = file("cluster", "r") 
for line in b: 
    L1 = line.split('\t') 
    # Make a presence/absence row for each line in the second file. 
    this_row = [1 if i in L1 else 0 for i in a_list] 
    final_matrix.append(this_row) 

for row in final_matrix: 
    print row 
    # You can get fancier with this because right now it will 
    # Print these out as lists. 

在這種情況下，最終的矩陣被保存爲列表的列表。