蟒蛇長3.6功能

Question

我有一個情況

if len(a) = 0 
    a = '' 
if len(b) = 0 
    b = '' 
if len(c) = 0 
    c = '' 

如果len（任何對象）爲零，其聲明爲空。 我必須繼續爲所有的字母做這個。對其進行編碼的最佳方式是什麼？

其他信息：

import test2 
x = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j'] # a b c are declared in test2 file as a = set()...b = set() ... 
for y, z in enumerate(x): 
    if len(getattr(test2, x[y])) >= 5: 
      setattr(test2, x[y], '') = '' 
    else: 
     pass 

爲什麼我不能SETATTR那裏使用？

Answer 1

下面的代碼舉例說明了一些可怕的編程習慣，但是我試圖理解你的請求（26個單字母變量，真的嗎？）。

a = "fshdj" 
b = "" 
c = "fshdj" 
d = "fshdj" 
e = "" 
f = "fshdj" 
g = "fshdj" 
h = "fshdj" 
i = "dj" 
j = "fshdj" 
k = "fshdj" 
j = "fsj" 
l = "fshdj" 
m = "fshdj" 
n = "fshdj" 
o = "f" 
p = "fshdj" 
q = "fshdj" 
r = " " 
s = "fshdj" 
t = "fshdj" 
u = "" 
v = "fshdj" 
w = "fshdj" 
x = "fshdj" 
y = "" 
z = "fshdjfshdj" 

alpha = [a , b, c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, u, v, w, x, y, z] 

for i in alpha: 
    if len(i) == 0: 
    i = None 
    print i 

Try it here!