我在不同的服務器上有兩個表,我需要鏈接它們有共同的列。但是,來自欄目的數據是非常不同的。SQL比較兩個數據略有差異的列
我有兩張桌子,一張是臨時桌,我有我需要的學生名單,他們的全名,學校,地址和課後課程以及課程ID,每個課程都有一個ID。另一個表格包含所有節目信息及其ID和位置,這些信息目前都在我們的系統中。
另一張表具有所有ID,但該數據長度爲5個字符,並非全部,但大部分數據都以'0'結尾。現在我需要加入這張在我的第一張桌子上有5個字符長的數據的桌子,並且說我的桌子上的ID與我的所有學生都屬於這個ID。
表#students:
StudentID Lastname Firstname dob Afterschool_program location Department programID
--------------------------------------------------------------------------------------------
81EB Toreros Christian 03/26/1999 Teen Dance Exercise 158-Bayshore Theater 5269
89EB Willis Michael 03/15/2002 Arts Painting 158-Mulan Drive Arts 6985
其他表位置:
locationName Address LocationID
---------------------------------------------------------------------------------------------------------------------
Bay Shore - DAY Program/Scie- TEEN & YOUNG ADULTS - 52690 BayShore 123-89 place 52690
Mulan - DAY Program/Arts- TEEN - 96850 BayShore 123-89 place 52690
問題是我怎麼能加入locationID
到programID
?
到目前爲止,我已經試過這
IF OBJECT_ID('tempdb..#locationsID') IS NOT NULL
DROP TABLE #locationsID
SELECT DISTINCT
LEFT(RTRIM(LocationID), 4) AS Location_ID, LocationName
INTO
#locationsID
FROM
locationstable
ORDER BY
LocationID
--select * from #locationsID
IF OBJECT_ID('tempdb..#locomparison') IS NOT NULL
DROP TABLE #locomparison
SELECT DISTINCT
cloc.LocationID, pfm.programID as programID
INTO
#locomparison
FROM
#locationsID cloc
LEFT OUTER JOIN
tablewithlivesystemdata pfm ON pfm.programID = cloc.Location_ID
ORDER BY
LocationID
--Main
SELECT
programID, LocationID, *
FROM
Students
JOIN
#locomparison ON LocationID.#locomparison = programID.#Students
但是這不工作:(
什麼是programID和lo的數據類型cationID?當你說不工作時,你有錯誤或執行,但沒有得到期望的結果? –