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我試圖發送一個HTTPRequest,對Web API,我,包括請求頭的用戶名和密碼,但我得到The format of value 'dGVzdGNsaWVudDAyOnBhc3MwMg==' is invalid
型「System.FormatException」未處理的異常發生在System.Net.Http.dll
HttpClientHandler handler = new HttpClientHandler();
HttpClient client = new HttpClient(handler);
String userName = "testclient02";
String userPassword = "pass02";
string authInfo = userName + ":" + userPassword;
authInfo = Convert.ToBase64String(Encoding.Default.GetBytes(authInfo));
// client.DefaultRequestHeaders.Authorization = new AuthenticationHeaderValue("Authorization", authInfo);//if use this i get 2 authorization tags in header- Authorization: Authorization XXXXXXXXX===
client.DefaultRequestHeaders.Add("Authorization", authInfo.ToString());//error here
var result = client.GetAsync(new Uri("http://localhost:007/api/XXX")).Result;
編輯:這是我的解碼碼
public class AuthenticationHandler : DelegatingHandler
{
public User ObjUser;
protected override Task<HttpResponseMessage> SendAsync(HttpRequestMessage request, CancellationToken cancellationToken)
{
try
{
var tokens = request.Headers.GetValues("Authorization").FirstOrDefault();
if (tokens != null)
{
byte[] data = Convert.FromBase64String(tokens);
string decodedString = Encoding.UTF8.GetString(data);
string[] tokensValues = decodedString.Split(':');
ObjUser = new CredentialChecker().CheckCredential(tokensValues[0], tokensValues[1]);
}
}
}
你可以給我一些建議/代碼示例解碼與基本認證 – prasy 2015-02-11 22:26:05
我也添加了解碼代碼。 – prasy 2015-02-11 22:35:38
@prasy看看這個博客:http://weblog.west-wind.com/posts/2013/Apr/18/A-WebAPI-Basic-Authentication-Authorization-Filter – 2015-02-11 23:05:11