Question

這是我通常會檢查空的結果：mysql_fetch_assoc

不過，我使用的PDO爲客戶和本次登錄的功能，我想返回一些文字或數字或布爾說連續被發現或不。

public function Login ($email,$password) 
{ 
    $sqlQuery="SELECT * FROM db_user WHERE email= '".$email."' AND password='".$password." '"; 
    $statement = $this->_dbHandle->prepare($sqlQuery); // prepare a PDO statement 
    $statement -> execute(); 

    $dataSet= []; 
    if(mysql_num_rows($statement) == 1){ 
    echo 'login true'; 
    } else { 
    echo 'login false'; 
    } 

Answer 1

兩個其他的答案基本上是不能接受的。
而不是因爲他們缺乏潔淨，而是因爲他們是非常危險的

public function Login ($email,$password) 
{ 
    $sql="SELECT 1 FROM db_user WHERE email=? AND password=?"; 
    $stmt = $this->_dbHandle->prepare($sql); 
    $statement -> execute([$email, $password]); 
    return $stmt->fetchColumn(); 
} 

你應該使用預處理語句，而不僅僅是模仿他們。

Answer 2

$sqlQuery="SELECT * FROM db_user WHERE email= '".$email."' AND password='".$password." '"; 
    $statement = $this->_dbHandle->prepare($sqlQuery); // prepare a PDO statement 
    $statement -> execute(); 
    $rows = $statement ->fetch(PDO::FETCH_ASSOC); 

    if(! $rows) 
    { 
    die('Empty Records'); 
    } 

Answer 3

$sqlQuery= "SELECT * FROM db_user WHERE email= ? AND password= ?"; 
    $statement = $this->_dbHandle->prepare($sqlQuery); // prepare a PDO 

    // pass parameter to tackle [SQL Injection][1] 
    $stmt->execute(array($email, $password)); 

    $result = $stmt->fetch(); 
    if($result) { 
     echo "login true"; 
    }else{ 
     echo "login false"; 
    }