計數和使用PHP的MySQL

Question

我想計數，並使用PHP的MySQL

name 
AAA 
BBB 
BBB 
BBB 
AAA 
CCC 

結果應該是在從下面的表中的列顯示每個重複的值顯示在一列中的每個重複的值如下面

AAA-2 
BBB-3 
CCC-1 

Answer 1

select name, count(name) as count from table_name group by name 

Answer 2

您需要：

select name,count(1) from yourtable group by name 

如果你需要用連字符輸出（ - ）

select concat(name,'-',count(1)) from yourtable group by name 

Answer 3

試試這個，

select name, count(*) from <table> group by name; 

Answer 4

SELECT name, COUNT(name) c_name FROM tablename GROUP BY name HAVING c_name>1 

Answer 5

<?php require_once('connection.php'); $result=mysqli_query($conn, "SELECT colum_name, concat(count(1),'-',colum_name) as colum_name FROM table_name group by colum_name order by colum_name desc"); while ( $data=mysqli_fetch_assoc($result)) { echo $data['colum_name']."<br>"; }