symfony2和樹枝上的子陣列

Question

好的，我有一個看起來像一個數組。

[0] => Array (
    first_name => j, 
    last_name => b, 
    times => Array(
    [0] => Array(
     [in1] => a date here 
     [out1] => a date here 
     [in2] => a date here 
     [out2] => a date here 
    ) 
    [1] => Array(
     [in1] => another date here 
     [out1] => another date here 
     [in2] => another date here 
     [out2] => another date here 
    ))) 

我已經簡化了陣列的SO佈局着想的樣子......

這份名單將時常有開始陣列中的超過100個不同的人，將所有需輸出到瀏覽器......這很好，我可以做..

{% for entity in entity %} 
<h3>{{ entity.first_name }} {{ entity.last_name }} ({{ start|date("m/d/Y") }} - {{ end|date("m/d/Y")}})</h3> 

<table = border="1" cellpadding="5" cellspacing="0"> 
     <thead> 
      <tr> 
       <th>Date</th> 
       <th>In</th> 
       <th>Lunch Out</th> 
       <th>Lunch In</th> 
       <th>Out</th> 
       <th>Extra In</th> 
       <th>Extra Out</th> 
       <th>Total Time</th> 
      </tr> 
     </thead> 
     <tbody> 
      {% for times in entity.times %} 
      <tr> 
       <td>{{ entity.times.daydate|date("M jS Y") }} </td> 
       <td>{{ entity.times.in1 is empty ? "" : entity.times.in1|date("h:i A") }}</td> 
       <td>{{ entity.times.out1 is empty ? "" : entity.times.out1|date("h:i A") }}</td> 
       <td>{{ entity.times.in2 is empty ? "" : entity.times.in2|date("h:i A") }}</td> 
       <td>{{ entity.times.out2 is empty ? "" : entity.times.out2|date("h:i A") }}</td> 
       <td>{{ entity.times.in3 is empty ? "" : entity.times.in3|date("h:i A") }}</td> 
       <td>{{ entity.times.out3 is empty ? "" : entity.times.out3|date("h:i A") }}</td> 
       <td>{{ entity.times.totaltime }} Hours</td> 
      </tr> 
      {% endfor%} 
     </tbody> 
</table> 
{% endfor %} 

這就是我目前的枝杈代碼...什麼我需要幫助，是因爲每一個「實體」擁有.times子數組，也需要循環..什麼是正確的方法來做到這一點？

Answer 1

{% for entity in entities %} 
    <h3>{{ entity.foo }}</h3> 

    {% for time in entity.times %} 
     <p>{{ time.bar }}</p> 
    {% endfor %} 
{% endfor %} 

我簡化了代碼，以便更容易地看到您正在尋找的概念。