多加入Laravel

Question

我需要進行兩個連接，但與許多條件語句那裏，我有這個

$matchThese = [ 'suspended' => 0, 'status' => 1, 'approved' => 1 ]; 

    $matchOther = [ 'status' => 1, 'approved' => 0 ]; 

    $deals = ListsDeals::where($matchThese)->where('stock', '>', 0)->orwhere($matchOther)->whereDate('end_date', '>', date('Y-m-d'))->limit(4)->offset(0)->orderBy('start_date')->get(); 

    $deals_lists = DB::table('deals') 
       ->join('list_has_deals', 'deals.id', '=', 'list_has_deals.deal_id' ) 
       ->join('lists', 'list_has_deals.list_id', '=', 'lists.id') 
       ->paginate(10); 

我需要兩個瓦爾一個唯一的查詢，選擇具有「何在」的所有交易在第一VAR並且隨後做出連接，問候。

Answer 1

我認爲可以做的伎倆：

$query = ListsDeals::where($matchThese)->where('stock', '>', 0)->orwhere($matchOther)->whereDate('end_date', '>', date('Y-m-d'))->limit(4)->offset(0)->orderBy('start_date'); 

$results = $query->join('list_has_deals', 'deals.id', '=', 'list_has_deals.deal_id' ) 
      ->join('lists', 'list_has_deals.list_id', '=', 'lists.id') 
      ->paginate(10);