查找只包含給定成分的食譜匹配行

Question

我在MySql中有三個表格RECIPES,INGREDIENTS和RECIPE_INGREDIENTS。現在我想獲取僅包含配料ID的食譜。我簡單的語言，我想搜索食譜，我可以從我有成分。

SELECT r.id 
FROM Recipes AS r 
INNER JOIN Recipe_ingredients AS ri ON r.id = ri.recipe_id 
INNER JOIN Ingredients AS i ON i.id = ri.ingredient_id 
WHERE i.id IN (... list of ids here ...) 
GROUP BY r.id 
HAVING COUNT(DISTINCT i.id) <= n -- where n is the number of the ingredient ids 
           -- specified in the list of the where clause 

編輯：如果你想獲得食譜，不要

Answer 1

你可以爲了得到配方的IDS有全部或部分的指定成分的使用以下查詢t包含指定列表中未包含的任何成分，則可以使用：

SELECT r.id 
FROM Recipes AS r 
LEFT JOIN Recipe_ingredients AS ri ON r.id = ri.recipe_id 
LEFT JOIN Ingredients AS i ON i.id = ri.ingredient_id 
WHERE i.id NOT IN (... list of ids here ...) 
GROUP BY r.id 
HAVING COUNT(i.id) = 0