我有這樣的一個表:SQLite的多個地方在同一列
Char1 Char2 Difficulty
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jon sara 1
pablo victor 2
laura patricia 1
marta juanjo 3
marina goku 4
我想選擇其中的難度= 1和難度= 2。我試圖做的所有行:
"SELECT * FROM " + table + " WHERE " + DatabaseOpenHelper.COLUMN_DIFFICULTY + " LIKE '1%'" + " AND " + DatabaseOpenHelper.COLUMN_DIFFICULTY + " LIKE '2%'"
但它不工作,我是SQLite的新手,所以我會很感激任何解釋與答案。謝謝!
由於難度列是INT類型,您爲什麼使用LIKE? –