從字典陣列中獲取值bash

Question

我在學習如何bash腳本，並且我需要知道如何從字典數組中獲取值。我這樣做的聲明：

declare -a persons 
declare -A person 
person[name]="Bob" 
person[id]=12 
persons[0]=$person 

如果我下面的正常工作：

echo ${person[name]} 
# Bob 

但是，當我試圖從陣列訪問值這是行不通的。我試過這些選項：

echo ${persons[0]} 
# empty result 
echo ${persons[0][name]} 
# empty result 
echo persons[0]["name"] 
# persons[0][name] 
echo ${${persons[0]}[name]} #It could have worked if this work as a return 
# Error 

我不知道還有什麼更多的嘗試。任何幫助，將不勝感激！

謝謝您的閱讀！

猛砸版本：48年3月4日

Answer 1

多維數組的概念是不bash支持，所以

${persons[0][name]} 

將無法​​正常工作。但是，從Bash 4.0開始，bash具有關聯數組，您似乎已經嘗試過，這適合您的測試用例。例如，你可以這樣做：

#!/bin/bash 
declare -A persons 
# now, populate the values in [id]=name format 
persons=([1]="Bob Marley" [2]="Taylor Swift" [3]="Kimbra Gotye") 
# To search for a particular name using an id pass thru the keys(here ids) of the array using the for-loop below 

# To search for name using IDS 

read -p "Enter ID to search for : " id 
re='^[0-9]+$' 
if ! [[ $id =~ $re ]] 
then 
echo "ID should be a number" 
exit 1 
fi 
for i in ${!persons[@]} # Note the ! in the beginning gives you the keys 
do 
if [ "$i" -eq "$id" ] 
then 
    echo "Name : ${persons[$i]}" 
fi 
done 
# To search for IDS using names 
read -p "Enter name to search for : " name 
for i in "${persons[@]}" # No ! here so we are iterating thru values 
do 
if [[ $i =~ $name ]] # Doing a regex match 
then 
    echo "Key : ${!persons[$i]}" # Here use the ! again to get the key corresponding to $i 
fi 
done