在ruby中刪除重複的數據

Question

我想基於所有三個字段，即基於事件名稱，日期和時間從我的代碼中刪除重複項，如果所有三個字段都匹配兩個事件，則應刪除一個，只顯示唯一events。我寫的代碼僅適用於一個字段，即根據eventname刪除條目。如何匹配所有三個字段。我正在使用&，但沒有成功。

include Enumerable 

list = [ 
    { 
    :eventname => "music show", 
    :date => "1st august", 
    :time => "9 pm" 
    }, 
    { 
     :eventname => "dance show", 
     :date => "11st august", 
     :time => "9 pm" 
    }, 
    { 
     :eventname => "music show", 
     :date => "1st august", 
     :time => "9 pm" 
    }, 
    { 
     :eventname => "music show", 
     :date => "15st august", 
     :time => "9 pm" 
    }, 
    { 
     :eventname => "magic show", 
     :date => "12st august", 
     :time => "9 pm" 
    }, 
    { 
     :eventname => "rock show", 
     :date => "1st august", 
     :time => "9 pm" 
    } 
] 

b=list.group_by{|r| r[:eventname]}.map do |k, v| 
    v.inject({}) { |r, h| r.merge(h){ |key, o, n| o || n } } 
end 

Answer 1

使用uniq mthod的Array：

list.uniq