我對PHP相當陌生,並且在重新顯示帶有更新數據的表單時遇到問題;重新顯示包含更新數據的表單
迄今爲止的故事:
我有一個電子郵件地址來標識一個「用戶」註冊和登錄頁面;在登錄時,用戶被帶到自己的「會員」頁面,該頁面將顯示該人員持有的個人數據。如果他們願意的話,他們會被邀請編輯這些數據。這將把他們帶到'更新'頁面,完成後,數據庫通過(隱藏)'update + ac'頁面更新,然後返回到他們自己的'主'頁面。問題是,我無法獲取「成員」頁面,然後在表單中重新顯示更新的數據,也無法將表單重新顯示。
下面是「成員」頁面培訓相關代碼:(我還沒有編碼的任何安全性或有效性尚未 - 部份都是在本地主機上 - 我想加時賽得到的編碼右第一)
<?php
include_once 'login.php';
include_once 'functions.php';
if (isset($_SESSION['user']))
{
$user = $_SESSION['user'];
mysql_connect($dbhost, $dbuser, $dbpass) or die(mysql_error());
mysql_select_db($dbname) or die("Unable to connect: " . mysql_error());
$data = "SELECT * FROM `names` WHERE email='$user'";
$result=mysql_query($data) or die(mysql_error());
while($row=mysql_fetch_array($result)){
}
?>
<table border='1px' style="background-color:#F0F8FF; font-weight: bold;" >
<caption>Personal Record</caption>
<tr>
<th>ID</th>
<td><?php
echo $row['id'];
?></td>
</tr>
<tr>
<th>Name</th>
<td><?php
echo $row['name'];
?></td>
</tr>
<tr>
<th>E-Mail</th>
<td><?php
echo $row['email'];
?></td>
</tr>
<tr>
<th>Main Telephone</th>
<td><?php
echo $row['maintel'];
?></td>
</tr>
<tr>
<th>Mobile Telephone</th>
<td><?php
echo $row['mobtel'];
?></td>
</tr>
<tr>
<th>Organisation</th>
<td><?php
echo $row['organisation'];
?></td>
</tr>
<tr>
<th>Group Leader</th>
<td><?php
echo $row['group_leader'];
?></td>
</tr>
<tr>
<th>Supervisor</th>
<td><?php
echo $row['supervisor'];
?></td>
</tr>
<tr>
<th>Volunteer</th>
<td><?php
echo $row['volunteer'];
?></td>
</tr>
<tr>
<th>Assessor</th>
<td><?php
echo $row['assessor'];
}
?></td>
</tr>
</table>
<p><br />
<form method="post" action="update.php">
<input name="Submit1" type="submit" value="Edit" style="width: 67px" /></form>
</p>
<p> </p>
以下是該 'update.php' 頁面的代碼:
<?php
include_once 'login.php';
include_once 'functions.php';
session_start();
// Connect to server and select database.
mysql_connect($dbhost, $dbuser, $dbpass) or die(mysql_error());
mysql_select_db($dbname) or die("Unable to connect: " . mysql_error());
// get value of id that sent from address bar
if (isset($_SESSION['user']))
{
$user = $_SESSION['user'];
// Retrieve data from database
$sql="SELECT * FROM names WHERE email='$user'";
$result=mysql_query($sql);
$rows=mysql_fetch_array($result);
}
?>
<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<form name="form1" method="post" action="update_ac.php">
<td>
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<tr>
<td> </td>
<td colspan="3"><strong>Update data in mysql</strong> </td>
</tr>
<tr>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
</tr>
<tr>
<td align="center"> </td>
<td align="center"><strong>Name</strong></td>
<td align="center"><strong>E-Mail</strong></td>
<td align="center"><strong>Main Tel</strong></td>
<td align="center"><strong>Mob Tel</strong></td>
<td align="center"><strong>Organisation</strong></td>
<td align="center"><strong>Group Leader</strong></td>
<td align="center"><strong>Supervisor</strong></td>
<td align="center"><strong>Volunteer</strong></td>
<td align="center"><strong>Assessor</strong></td>
</tr>
<tr>
<td> </td>
<td align="center"><input name="name" type="text" id="name" value="<? echo $rows['name']; ?>"></td>
<td><input name="email" type="text" id="email" value="<? echo $rows['email']; ?>" size="40"></td>
<td align="center"><input name="maintel" type="text" id="maintel" value="<? echo $rows['maintel']; ?>" size="15"></td>
<td align="center"><input name="mobtel" type="text" id="mobtel" value="<? echo $rows['mobtel']; ?>"></td>
<td align="center"><input name="organisation" type="text" id="organisation" value="<? echo $rows['organisation']; ?>"></td>
<td align="center"><input name="group_leader" type="text" id="group_leader" value="<? echo $rows['group_leader']; ?>"></td>
<td align="center"><input name="supervisor" type="text" id="supervisor" value="<? echo $rows['supervisor']; ?>"></td>
<td align="center"><input name="volunteer" type="text" id="volunteer" value="<? echo $rows['volunteer']; ?>"></td>
<td align="center"><input name="assessor" type="text" id="assessor" value="<? echo $rows['assessor']; ?>"></td>
</tr>
<tr>
<td> </td>
<td><input name="id" type="hidden" id="id" value="<? echo $rows['id']; ?>"></td>
<td align="center"><input type="submit" name="Submit" value="Submit"></td>
<td> </td>
</tr>
</table>
</td>
</form>
</tr>
</table>
<?
// close connection
mysql_close();
?>
最後,這裏是爲'upate_ac.php頁面代碼:
<?php
include_once 'login.php';
include_once 'functions.php';
// Connect to server and select database.
mysql_connect($dbhost, $dbuser, $dbpass) or die(mysql_error());
mysql_select_db($dbname) or die("Unable to connect: " . mysql_error());
// update data in mysql database
$id = $_POST['id'];
$name = $_POST['name'];
$email = $_POST['email'];
$maintel = $_POST['maintel'];
$mobtel = $_POST['mobtel'];
$organisation = $_POST['organisation'];
$group_leader = $_POST['group_leader'];
$supervisor = $_POST['supervisor'];
$volunteer = $_POST['volunteer'];
$assessor = $_POST['assessor'];
$sql="UPDATE `names` SET id='$id', `name`='$name', `email`='$email', `maintel`='$maintel', `mobtel`='$mobtel', `organisation`='$organisation', `group_leader`='$group_leader', `supervisor`='$supervisor', `volunteer`='$volunteer', `assessor`='$assessor' WHERE `id`='$id''";
$result=mysql_query($sql);
// if successfully updated.
if($result){
echo "Successful";
echo "<BR>";
echo "<a href='member.php?view=$user'>View result</a>";
}
else {
echo "ERROR";
}
?>
會發生什麼,我會得到'成功'和'查看結果'。當我點擊'查看結果'時,我會進入'會員'頁面,但沒有顯示任何表格。
我將不勝感激任何幫助。
問候,
'H'
_(我還沒有編寫任何安全性或驗證 - 所有都在本地主機上 - 我想首先得到編碼的權利_一定不要忘記 - 好的做法是驗證和逃脫,因爲你去.... (大多數情況下,這個評論是爲了那些會錯過你的筆記在這個問題上的人,並且在這裏跳到關於SQL注入的問題上) – 2012-04-07 13:41:48
你應該使用正確的代碼縮進和你的html中的單獨代碼邏輯。 – 2012-04-07 13:54:43