即時嘗試採取std::string
值並將其用作分隔符std::getline()
函數 但沒有mater我編譯器給我錯誤。 這是我嘗試做的事:特林轉換爲在std :: getline分隔符中使用的str字符串
std::stringstream ss(s);
std::string item;
std::string delim ="&&=";
int ssize = delim.size();
int newssize = ssize+1;
char del[SSIZE]; // also here when i try gives error
strcpy(del,delim.c_str());
char * delrr[1024] = delim.c_str(); //gives error
while(std::getline(ss,item,delrr)) {
elems.push_back(item);
}
錯誤即時得到大約總是要爲const char *皈依。
error C2440: 'initializing' : cannot convert from 'const char *' to 'char *[1024]'
1> There are no conversions to array types, although there are conversions to references or pointers to arrays
1>.\UT.cpp(179) : error C2780: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &)' : expects 2 arguments - 3 provided
1> d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(527) : see declaration of 'std::getline'
1>.\UT.cpp(179) : error C2784: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &,const _Elem)' : could not deduce template argument for 'std::basic_istream<_Elem,_Traits> &' from 'std::stringstream'
1> d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(475) : see declaration of 'std::getline'
1>.\UT.cpp(179) : error C2784: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &,const _Elem)' : could not deduce template argument for 'std::basic_istream<_Elem,_Traits> &' from 'std::stringstream'
1> d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(475) : see declaration of 'std::getline'
1>.\UT.cpp(179) : error C2782: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &,const _Elem)' : template parameter '_Elem' is ambiguous
1> d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(475) : see declaration of 'std::getline'
1> could be 'char **'
1> or 'char'
UPDATE:
找到了答案: How do I tokenize a string in C++?
http://www.codeproject.com/Articles/23198/C-String-Toolkit-StrTk-Tokenizer
你可能想要* char delrr [1024] *而不是* char * delrr [1024] * – Gigi 2012-02-09 16:50:40
請退後一步,用英文解釋你真正想做的事情,而不用提到任何實現細節。 – 2012-02-09 17:04:34
如果我刪除* – user63898 2012-02-09 17:09:42