Mysqli編寫的聲明沒有選擇

Question

我有一個if語句與登錄頁面一起使用。

我一直在試圖將它轉換爲mysqli預處理語句。它以前只是普通的mysqli。

問題是無論我輸入什麼ID，都會說無效的ID！而不是切換到正確的頁面。

if (isset($_POST['login'])) 
{ 
require "connect.php"; 

session_start(); 

if (count($_POST) > 0) 
    { 
    if ($stmt = mysqli_prepare($conn, "SELECT id, Login_ID, Name, User_Role_ID FROM user WHERE Login_ID = ?")); 

    $lid = $_POST["id"]; 

    $stmt->bind_param("i", $lid); 

    $stmt->execute(); 

    $stmt->bind_result($id, $Login_ID, $Name, $User_Role_ID); 

     $_SESSION["Student_DB_ID"] = $id; 
     $_SESSION["Login_ID"] = $Login_ID; 
     $_SESSION["Name"] = $Name; 
     $_SESSION["User_Role_ID"] = $User_Role_ID; 

     switch ($User_Role_ID) 
      { 
     case "2": 
      header("Location: ../views/student/"); 
      break; //Student 
     case "1": 
      header("Location: ../views/admin/"); 
      break; //Admin 
     default: 
       echo "Invalid ID!"; 
      } 

/* close statement */ 
$stmt->close(); 
$conn->close(); 

    } 
} 

Answer 1

你需要閱讀文檔的mysqli_stmt_fetch（）函數（http://php.net/manual/en/mysqli-stmt.fetch.php）。該函數僅返回布爾值，具體取決於查詢是否成功完成。您需要使用bind_result（）來返回值。

編輯：

按照下面的評論，此代碼應工作，你也刪除取（）調用，它仍然是必要的：

if (isset($_POST['login'])) { 
    require "connect.php"; 

    session_start(); 

    if (count($_POST) > 0) { 
     if ($stmt = mysqli_prepare($conn, "SELECT id, Login_ID, Name, User_Role_ID FROM user WHERE Login_ID = ?")) { 
      $lid = $_POST["id"]; 

      $stmt->bind_param("i", $lid); 
      $stmt->execute(); 
      $stmt->bind_result($id, $Login_ID, $Name, $User_Role_ID); 
      $stmt->fetch(); 

      $_SESSION["Student_DB_ID"] = $id; 
      $_SESSION["Login_ID"] = $Login_ID; 
      $_SESSION["Name"] = $Name; 
      $_SESSION["User_Role_ID"] = $User_Role_ID; 

      switch ($User_Role_ID) { 
       case "2": 
        header("Location: ../views/student/"); 
        break; //Student 
       case "1": 
        header("Location: ../views/admin/"); 
        break; //Admin 
       default: 
        echo "Invalid ID!"; 
      } 

      /* close statement */ 
      $stmt->close(); 
      $conn->close(); 
     } 
    } 
}