我在PHP中有這段代碼。它連接到數據庫罰款,但彈出一個錯誤,當tryinto插入信息。在PHP中查詢數據庫時出錯,MySQL
$dbc = mysqli_connect('localhost', 'root', 'marina', 'aliendatabase') or die('Error connecting to MySQL server.');
$query = "INSERT INTO aliens_abduction (name, email) VALUSE ('John', '[email protected]')";
$result = mysqli_query($dbc, $query) or die('Error querying database.');
mysqli_close($dbc);
以下是截圖:http://img532.imageshack.us/img532/2930/63306356.jpg
感謝, [R
''死 - >'trigger_error(mysqli_error()$查詢);' – 2010-04-02 12:58:33
如果你告訴我們,這將是有益**這**錯誤你得到:) – 2010-04-02 13:03:12
警告:mysqli_error()期望恰好1參數,0給出在C:\ xampp \ xampp \ htdocs \ rob \ report.php在線43 注意:INSERT INTO aliens_abduction(name,email)第43行的C:\ xampp \ xampp \ htdocs \ rob \ report.php中的VALUES('John','john[email protected]') – 2010-04-02 13:05:21