javascript pow參數 - 阿姆斯壯數字

Question

試圖寫出阿姆斯壯功能。我使用chrome進行調試，發現它在val1上炸彈，當我嘗試分配pow的結果時。我嘗試了數組[元素]和數組[元素] .value，但它不喜歡。

//Armstrong numbers 
 
function armstrong() { 
 

 
var numberStr = document.getElementById('inputNumber').value; 
 
var numberInt = parseInt(numberStr); 
 
var arrayOfNum = numberStr.split(''); 
 
var val1, val2, val3, total = 0; 
 
    
 
var displayResult = document.getElementById('displayResult'); 
 

 
for (i = 0; i < arrayOfNum.length; i++) { 
 
    arrayOfNum[i] = parseInt(arrayOfNum[i]); 
 
} 
 

 
if (arrayOfNum.length === 3) { 
 
    val1 = Math.pow(arrayOfNum[0], 3); 
 
    val2 = Math.pow(arrayOfNum[1], 3); 
 
    val3 = Math.pow(arrayOfNum[2], 3); 
 
    
 
    total = val1 + val2 + val3; 
 

 
    if (total === numberInt) { 
 
     //display msg that number is armstrong 
 
     displayResult.innerHTML = "Your number " + numberInt + " is an Armstrong Number."; 
 
    } else { 
 
     //display msg that not armstrong 
 
     displayResult.innerHTML = "Your number " + numberInt + " is NOT an Armstrong Number."; 
 
    } 
 
} else { 
 
    // display msg to enter a 3 digit number   
 
    displayResult.innerHTML = "You must enter a 3 digit number."; 
 
} 
 
}

Answer 1

您使用戰俘。在JavaScript的其Math.pow（） 取代你的代碼，上面已經被編輯以顯示解決方案這

val1 = Math.pow(arrayOfNum[0].value, 3); 
val2 = Math.pow(arrayOfNum[1].value, 3); 
val3 = Math.pow(arrayOfNum[2].value, 3);