如何使用JAXB

Question

這是我的XML來獲取XML屬性：

<?xml version="1.0" encoding="UTF-8" ?> 
    <organization> 
     <bank> 
     <description>aaa</description> 
     <externalkey>123</externalkey> 
     <property name="pName" value="1234567890" /> 
     </bank> 
    </organization> 

我使用JAXB和解組對這個XML，我可以得到說明和externalkey。但我無法獲得有價值的物業名稱。

• 這是我和解組Java類：

  JAXBContext jb = JAXBContext.newInstance(Organization.class); 
  Unmarshaller um = jb.createUnmarshaller(); 
  Organization org = (Organization) um.unmarshal(new File("\\upload\\bank999999.xml")); 
  System.out.println(org.getBank().getDescription()); 
  System.out.println(org.getBank().getExternalkey()); 
  

• Organization.java

  @XmlRootElement 
  public class Organization { 
  Bank bank = new Bank(); 
  
  public Bank getBank() { 
      return bank; 
  } 
  
  public void setBank(Bank bank) { 
  this.bank = bank; 
  } 
  } 
  

• Bank.java

  @XmlRootElement 
  public class Bank { 
  private String description; 
  private String externalkey; 
  private String property; 
  
  //..GETTER and SETTER 
  } 
  

  我怎樣才能獲得屬性名和價值è？感謝ü

Answer 1

銀行

您需要從String的property屬性更改爲一個域對象。

@XmlAccessorType(XmlAccessType.FIELD) 
public class Bank { 
    private String description; 
    private String externalkey; 
    private Property property; 
} 

物業

然後你Property物體看起來是這樣的：

@XmlAccessorType(XmlAccessType.FIELD) 
public class Property { 

    @XmlAttribute 
    private String name; 

    @XmlAtrribute 
    private String value; 

}