交叉這兩個列表的最好方法是什麼？

Question

我在C＃2名列表：

public class AvailableSlot 
{ 
    public DateTime DateTime; 
    public string Name 
} 

List<AvailableSlot> list1 = GetList(); 
List<AvailableSlot> list2 = GetAnotherList(); 

我想打電話給相交這些列表中找出有兩個列表中同一日期的項目。我知道我可以使用.Intersect來獲取這個信息，但我有一個稍微複雜的要求。我想返回一個相交的列表，但我想要這個列表包含一個列表中包含所有名稱的對象。所以是這樣的：

List<AvailableSlot2> intersectedList . .. 

其中AvailableSlot2是下面這樣：

public class AvailableSlot2 
{ 
    public DateTime DateTime; 
    public string[] Names; 
} 

有沒有嘗試兩個列表之間相交後做這種轉變的能力？

Answer 1

我只想工會這兩個列表，按日期時間，然後從組拉出名稱：

var list1 = new List<AvailableSlot> 
{ 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 1), Name = "Alpha" }, 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 2), Name = "Bravo" }, 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 3), Name = "Charlie" }, 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 1), Name = "Delta" }, 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 2), Name = "Echo" }, 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 3), Name = "Foxtrot" }, 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 4), Name = "Golf" }, 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 5), Name = "Hotel" } 
}; 

var list2 = new List<AvailableSlot> 
{ 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 1), Name = "Apple" }, 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 2), Name = "Bannana" }, 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 1), Name = "Dog" }, 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 2), Name = "Egg" }, 
    new AvailableSlot { DateTime = new DateTime(2013, 2, 5), Name = "Hi" } 
}; 

var list3 = list1.Where (l => list2.Where (li => l.DateTime == li.DateTime).Any()) 
    .Union(list2.Where (l => list1.Where (li => l.DateTime == li.DateTime).Any())); 

var groupedItems = from slot in list3 
    group slot by slot.DateTime into grp 
    select new AvailableSlot2 { 
     DateTime = grp.Key, 
     Names = grp.Select (g => g.Name).ToArray() 
    }; 

foreach(var g in groupedItems) 
{ 
    Console.WriteLine(g.DateTime); 
    foreach(var name in g.Names) 
     Console.WriteLine(name); 
    Console.WriteLine("---------------------"); 
} 

輸出：

2/1/2013 12:00:00 AM 
Alpha 
Delta 
Apple 
Dog 
--------------------- 
2/2/2013 12:00:00 AM 
Bravo 
Echo 
Bannana 
Egg 
--------------------- 
2/5/2013 12:00:00 AM 
Hotel 
Hi 
--------------------- 

Answer 2

您可以使用LINQ到對象Join()排隊用相同的日期時間屬性項，然後收集所有的名字到一個數組

var joinedItems = from slot1 in list1 
        join slot2 in list2 
        on slot1.DateTime equals slot2.DateTime into g 
        where g.Any() 
        select new AvailableSlot2 
        { 
         DateTime = slot1.DateTime, 
         Names = Enumerable.Range(slot1.Name,1).Union(g.Select(s => s.Name)).ToArray() 
        } 

Answer 3

您可以使用ToLookup：

DateTime dt1 = new DateTime(2013, 2, 1); 
DateTime dt2 = new DateTime(2013, 3, 1); 
DateTime dt3 = new DateTime(2013, 4, 1); 

var list1 = new List<AvailableSlot> 
{ 
    new AvailableSlot{DateTime = dt1, Name = "n1",}, 
    new AvailableSlot{DateTime = dt2, Name = "n2",}, 
    new AvailableSlot{DateTime = dt1, Name = "n3",}, 
}; 

var list2 = new List<AvailableSlot> 
{ 
    new AvailableSlot{DateTime = dt1, Name = "n1",}, 
    new AvailableSlot{DateTime = dt2, Name = "n2",}, 
    new AvailableSlot{DateTime = dt3, Name = "n3",}, 
}; 

var intersected = list1.Select (l => l.DateTime). 
         Intersect(list2.Select (l => l.DateTime)); 

var lookup = list1.Union(list2).ToLookup (
           slot => slot.DateTime, slot => slot); 

lookup.Where (l => intersected.Contains(l.Key)).Select (
    slot => new 
    { 
     DateTime=slot.Key, 
     Names=slot.Select (s => s.Name) 
    }); 

在這種情況下給出結果：

DateTime   Names 

01/02/2013 00:00 n1 
        n3 
        n1 

01/03/2013 00:00 n2 
        n2 

你當然可以使用同樣的名稱= slot.Select（S => s.Name）.Distinct （）來獲得一個明確的名稱列表。