我的sql腳本有什麼問題？無法保存當前時間的時間戳

Question

結果總是0000-00-00 00:00:00每次我發佈一個飼料

$sql = "INSERT INTO feed (feed, created, user_id_fk) VALUES (:feed,:created,:user_id)"; 
     $stmt = $db->prepare($sql); 
     $stmt->bindParam("feed", $feed, PDO::PARAM_STR); 
     $stmt->bindParam("user_id", $user_id, PDO::PARAM_INT); 
     $created = time(); 
     $stmt->bindParam("created", $created, PDO::PARAM_INT); 
     $stmt->execute(); 

Answer 1

我認爲這是更好地使用date()而不是time()。我想向你提出這樣的建議。

//Get time 
date_default_timezone_set("America/Adak"); //Set the correct time zone here. 
$created = date("Y-m-d H:i:s"); //Output looks like 2001-03-10 17:16:18 

$sql = "INSERT INTO feed (feed, created, user_id_fk) VALUES (:feed,:created,:user_id)"; 
     $stmt = $db->prepare($sql); 
     $stmt->bindParam(":feed", $feed, PDO::PARAM_STR); 
     $stmt->bindParam(":user_id", $user_id, PDO::PARAM_INT);   
     $stmt->bindParam(":created", $created, PDO::PARAM_STR); 
     $stmt->execute(); 

如果您需要了解支持的時區，然後這裏是link