我可以通過任何方式優化以下查詢:Linq2SQL:優化查詢?
目標是嘗試找到類型4的客戶,該類型4也基於其增值稅和電子郵件而存在爲類型2。客戶端可以有一個或多個客戶端用戶。
(我都合適的指標設置,我保證)
from e in Clients.Where(h => h.ClientTypeId==4)
join u in ClientUsers on e.Id equals u.ClientId
where
e.DeleteFlag.Equals("n") &&
(
(!(e.VAT == null || e.VAT.Equals("")) && Clients.Any(f => f.ClientTypeId == 2 && f.VAT.Equals(e.VAT)))
|| (!(e.Email == null || e.Email.Equals("")) &&
(
Clients.Any(f => f.ClientTypeId == 2 && f.Email.ToLower().Equals(e.Email.ToLower()))
|| (from f in ClientUsers join q in Clients on f.ClientId equals q.Id where f.Email.Equals(e.Email.ToLower()) && q.ClientTypeId == 2 select f.Id).Any()
)
)
|| (!(u.Email == null || u.Email.Equals("")) &&
(
Clients.Any(f => f.ClientTypeId == 2 && f.Email.ToLower().Equals(u.Email.ToLower()))
|| (from f in ClientUsers join q in Clients on f.ClientId equals q.Id where f.Email.Equals(u.Email.ToLower()) && q.ClientTypeId == 2 select f.Id).Any()
)
)
)
select e
結果:
-- Region Parameters
DECLARE @p0 VarChar(1) SET @p0 = 'n'
DECLARE @p1 NVarChar(1) SET @p1 = ''
DECLARE @p2 Int SET @p2 = 2
DECLARE @p3 NVarChar(1) SET @p3 = ''
DECLARE @p4 Int SET @p4 = 2
DECLARE @p5 Int SET @p5 = 2
DECLARE @p6 NVarChar(1) SET @p6 = ''
DECLARE @p7 Int SET @p7 = 2
DECLARE @p8 Int SET @p8 = 2
DECLARE @p9 Int SET @p9 = 4
-- EndRegion
SELECT [t0].[Id], [t0].[AccountId], [t0].[CompanyName], [t0].[Address], [t0].[Address2], [t0].[PostCode], [t0].[PostArea], [t0].[ContactPerson], [t0].[Phone], [t0].[Email], [t0].[VAT], [t0].[Webpage], [t0].[Description], [t0].[Active], [t0].[PreRegcode], [t0].[PreRegcheck], [t0].[AccountCreated], [t0].[UpdateTimeStamp], [t0].[DeleteFlag], [t0].[ClientTypeId], [t0].[CampaignCodeId], [t0].[PayexId], [t0].[ApiKey], [t0].[InvoiceName], [t0].[Source], [t0].[ProspectStatusId], [t0].[ProspectLastCommentId], [t0].[ProspectCallbackDate]
FROM [Clients] AS [t0]
INNER JOIN [ClientUsers] AS [t1] ON ([t0].[Id]) = [t1].[ClientId]
WHERE ([t0].[DeleteFlag] = @p0) AND (((NOT (([t0].[VAT] IS NULL) OR ([t0].[VAT] = @p1))) AND (EXISTS(
SELECT NULL AS [EMPTY]
FROM [Clients] AS [t2]
WHERE ([t2].[ClientTypeId] = @p2) AND ([t2].[VAT] = [t0].[VAT])
))) OR ((NOT (([t0].[Email] IS NULL) OR ([t0].[Email] = @p3))) AND ((EXISTS(
SELECT NULL AS [EMPTY]
FROM [Clients] AS [t3]
WHERE ([t3].[ClientTypeId] = @p4) AND (LOWER([t3].[Email]) = LOWER([t0].[Email]))
)) OR (EXISTS(
SELECT NULL AS [EMPTY]
FROM [ClientUsers] AS [t4]
INNER JOIN [Clients] AS [t5] ON [t4].[ClientId] = ([t5].[Id])
WHERE ([t4].[Email] = LOWER([t0].[Email])) AND ([t5].[ClientTypeId] = @p5)
)))) OR ((NOT (([t1].[Email] IS NULL) OR ([t1].[Email] = @p6))) AND ((EXISTS(
SELECT NULL AS [EMPTY]
FROM [Clients] AS [t6]
WHERE ([t6].[ClientTypeId] = @p7) AND (LOWER([t6].[Email]) = LOWER([t1].[Email]))
)) OR (EXISTS(
SELECT NULL AS [EMPTY]
FROM [ClientUsers] AS [t7]
INNER JOIN [Clients] AS [t8] ON [t7].[ClientId] = ([t8].[Id])
WHERE ([t7].[Email] = LOWER([t1].[Email])) AND ([t8].[ClientTypeId] = @p8)
))))) AND ([t0].[ClientTypeId] = @p9)
查詢工作,但需要5分鐘來運行。
過多少數據? – 2009-09-30 08:12:35
54641客戶(每個客戶今天只有一個ClientUser)。類型2的4544和類型4的30287. – 2009-09-30 08:14:57
我認爲,如果您描述表格以及想要完全替代的內容,則會更容易。還要確保你在這些列上有索引。 – Runeborg 2009-09-30 09:19:45