郵政編碼和檢索它們

Question

在這段代碼中，我想查詢一個名爲「zipcodes」的表。我想首先檢查輸入的郵政編碼是否是有效的郵政編碼。那麼如果它是一個有效的郵政編碼，我想檢索與匹配的經度，緯度，城市，&狀態的郵政編碼。

然後，在檢索它們之後，我想將它們放到另一個名爲「Users」的表中。一旦進入Users表，我希望能夠將分配給它們的值在我的網站上的各個位置進行回顯。

<?php 

    $query = mysqli_query($con, "SELECT * FROM zipcodes WHERE ZIP='".$user_zip."'"); 

    if(mysqli_num_rows($query) > 0){ 

     echo "Please Reenter A Valid Zip Code"; 
     { 

     }elseif(mysqli_num_rows($query) > 1){ 
     mysqli 
     // Need to put next line of code in users db 
      }elseif (mysqli_num_rows($query) > 1($con, "INSERT INTO ")){ 





     // retrieve from the database the city and state 
    }elseif ($user_zip == true($query = mysqli_query($con, "SELECT * FROM zipcodes ZIP,Latitude,Longitude,City,State WHERE ZIP='".$zip.", Latitude='".$latitude"', Longitude='".$longitude"', City='".$local"', State='".$country"', "'")) { 


    { 


    } 


    ?> 

Answer 1

這是對您的代碼的快速審查。這裏沒有其他答案。我的意見從// :開始。我已經修復了基本的語法並縮進了代碼以使其可讀。

<?php 

$query = mysqli_query($con, "SELECT * FROM zipcodes WHERE ZIP='".$user_zip."'"); 

// : Checking if there are 0 or more rows returned. 
if(mysqli_num_rows($query) > 0) { 
    echo "Please Reenter A Valid Zip Code"; 
// } << : Need a closing bracket here. 

{ // : These curlies must be for decorative purposes? 
} 

// : "If 0 or more rows; else if 1 or more rows". 
// : This'd never run because a previous condition matches; 1 > 0! 
elseif(mysqli_num_rows($query) > 1) { 
    mysqli 
    // Need to put next line of code in users db 
} 

// : You already matched the > 1 condition above. + syntax error! 
elseif (mysqli_num_rows($query) > 1($con, "INSERT INTO ")) { 

// : Fixing that syntax. You probably meant something like: 

elseif (mysqli_num_rows($query) > 1) { 
    mysqli($con, "INSERT INTO [...] "); 
} 

// : This is totally garbled up, both the PHP and the SQL query: 

// retrieve from the database the city and state 
/* 
elseif ($user_zip == true($query = mysqli_query($con, "SELECT * FROM zipcodes ZIP,Latitude,Longitude,City,State WHERE ZIP='".$zip.", Latitude='".$latitude"', Longitude='".$longitude"', City='".$local"', State='".$country"', "'")) { 
*/ 

// : You probably meant something like: 

elseif ($user_zip == true) { 
    $query = mysqli_query($con, 
     "SELECT * FROM zipcodes 
      WHERE ZIP='{$zip}' 
       AND Latitude='{$latitude}' 
       AND Longitude='{$longitude}' 
       AND City='{$local}' 
       AND State='{$country}'"); 
} 

世界上沒有什麼魔法可以使這項工作 - 即使所有的語法都糾正了。我建議你先花一點時間學習PHP（和MySQL）的語法。然後思考你想做什麼的邏輯。然後嘗試在你的代碼中表達。開始編寫最簡單的測試代碼。然後工作你的方式更復雜的東西。祝你好運，快樂學習。