消毒句子PHP中的preg_replace

Question

這是我目前的句子消毒功能：

$string = '  Helloooooo my frieeend!!!What are you doing?? Tell me what you like...........,please. '; 

結果是：

echo sanitize_sentence($string); 
Helloooooo my frieeend! ! ! What are you doing? ? Tell me what you like. . . . . . . . . . . , please. 

由於

# sanitize sentence 
function sanitize_sentence($string) { 
    $string = preg_replace("/(?<!\d)[.,!?](?!\d)/", '$0 ', $string); # word,word. > word, word. 
    $string = preg_replace("/(^\s+)|(\s+$)/us", "", preg_replace('!\s+!', ' ', $string)); # " hello hello " > "hello hello" 
    return $string; 
} 

與此字符串運行一些測試你可以看到，我已經設法解決了一些要求，但我仍然堅持一些細節。最終的結果應該：

Helloo my frieend! What are you doing? Tell me what you like..., please. 

這意味着，所有這些要求，應做到：

1. 只能有一個或三個連續週期。或...
2. 只能有一個連續的逗號，
3. 只能有一個連續的問號？
4. 可以只有一個連續的感嘆號！
5. 一封信一個字不能重複超過2次。例如爲：質量（右），masss（錯了，應轉換爲質量）
6. 的空間應該總是這些字符後加入，！？這已經很好了！
7. 在連續3個週期的情況下，該空間僅在上一個週期後添加。
8. 額外的空格（多於一個空格）應從句子的兩端刪除和修剪。 這已經很好了！

Answer 1

我覺得正則表達式是這是一個非常合適的技術。畢竟，這完全是消極的。不是語法或語法更正。

function sanitize_sentence($i) { 

    $o = $i; 

    // There can be only one or three consecutive periods . or ... 
    $o = preg_replace('/\.{4,}/','… ',$o); 
    $o = preg_replace('/\.{2}/','. ',$o); 

    // There can be only one consecutive "," 
    $o = preg_replace('/,+/',', ',$o); 

    // There can be only one consecutive "!" 
    $o = preg_replace('/\!+/','! ',$o); 

    // There can be only one consecutive "?" 
    $o = preg_replace('/\?+/','? ',$o); 

    // we just preemptively added a bunch of spaces. 
    // Let's remove any spaces between punctuation marks we may have added 
    $o = preg_replace('/([^\s\w])\s+([^\s\w])/', '$1$2', $o); 

    // A letter cannot repeat itself more than 2 times in a word 
    $o = preg_replace('/(\w)\1{2,}/','$1$1',$o); 

    // Extra spaces should be eliminated 
    $o = preg_replace('/\s+/', ' ', $o); 
    $o = trim($o); 

    // we want three literal periods, not an ellipsis char 
    $o = str_replace('…','...',$o); 

    return $o; 
} 

Answer 2

我想我會一次回答一個問題，因爲一次只專注於一個任務而不是將它們全部集中在一起更有意義。

對於＃5，我建議([a-z])(\1{0,1})\1*用$1$2代替，如看到in this example。

它需要輸入

 Helloooooo my frieeend!!!What are you doing?? Tell me what you like...........,please. 

併產生輸出

 Helloo my frieend!!!What are you doing?? Tell me what you like...........,please. 

Answer 3

對於＃1（。或...），(?<!\.)(\.{3}|\.)\.*\s*可以與$1更換（注意結尾空間），如this example所示。

這需要

 Helloooooo my frieeend!!!What are you doing?? Tell me what you like...........,please. 

，併產生輸出

 Helloooooo my frieeend!!!What are you doing?? Tell me what you like... ,please. 

正如你所看到的，你會得到一個時髦的... ,性格，這是一個更可能需要檢查的事情。除非您有另一個規則可用於刪除多個標點符號，否則您可以在執行此清理之前檢查.,或之後檢查. ,（之間的空格）。

這個生成的代碼，從regex101.com網站，如下：

$re = "/(?<!\\.)(\\.{3}|\\.)\\.*\\s*/"; 
$str = "  Helloooooo my frieeend!!!What are you doing?? Tell me what you like...........,please. "; 
$subst = "$1 "; 
$result = preg_replace($re, $subst, $str); 

Answer 4

＃2，＃3，＃4，你可以搜索([,?!])\1+\s*與$1替換（請注意之後的空間）如在this example中那樣。

這需要

 Helloooooo my frieeend!!!What are you doing?? Tell me what you like...........,please. 

，併產生

 Helloooooo my frieeend! What are you doing? Tell me what you like...........,please. 

生成的代碼看起來像：

$re = "/([,?!])\\1+\\s*/"; 
$str = "  Helloooooo my frieeend!!!What are you doing?? Tell me what you like...........,please. "; 
$subst = "$1 "; 
$result = preg_replace($re, $subst, $str);